Answer:
![E = 2.9775\times10^5 J](https://tex.z-dn.net/?f=E%20%3D%202.9775%5Ctimes10%5E5%20J)
Explanation:
Given: The latent heat of fusion for Aluminum is ![L = 3.97\times10^5 J/Kg](https://tex.z-dn.net/?f=L%20%3D%203.97%5Ctimes10%5E5%20%20J%2FKg)
mass to be malted m = 0.75 Kg
Energy require to melt E = mL
![E = 3.97\times10^5\times0.75 = 2.9775\times10^5 J](https://tex.z-dn.net/?f=E%20%3D%203.97%5Ctimes10%5E5%5Ctimes0.75%20%3D%202.9775%5Ctimes10%5E5%20J)
Therefore, energy required to melt 0.75 Kg aluminum
![E = 2.9775\times10^5 J](https://tex.z-dn.net/?f=E%20%3D%202.9775%5Ctimes10%5E5%20J)
Answer:
Part a)
![y_m = 0.157 mm](https://tex.z-dn.net/?f=y_m%20%3D%200.157%20mm)
part b)
![k = 101.8 rad/m](https://tex.z-dn.net/?f=k%20%3D%20101.8%20rad%2Fm)
Part c)
![\omega = 579.3 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%20579.3%20rad%2Fs)
Part d)
here since wave is moving in negative direction so the sign of
must be positive
Explanation:
As we know that the speed of wave in string is given by
![v = \sqrt{\frac{T}{m/L}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cfrac%7BT%7D%7Bm%2FL%7D%7D)
so we have
![T = 17.5 N](https://tex.z-dn.net/?f=T%20%3D%2017.5%20N)
![m/L = 5.4 g/cm = 0.54 kg/m](https://tex.z-dn.net/?f=m%2FL%20%3D%205.4%20g%2Fcm%20%3D%200.54%20kg%2Fm)
now we have
![v = \sqrt{\frac{17.5}{0.54}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cfrac%7B17.5%7D%7B0.54%7D%7D)
![v = 5.69 m/s](https://tex.z-dn.net/?f=v%20%3D%205.69%20m%2Fs)
now we have
Part a)
= amplitude of wave
![y_m = 0.157 mm](https://tex.z-dn.net/?f=y_m%20%3D%200.157%20mm)
part b)
![k = \frac{\omega}{v}](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%7B%5Comega%7D%7Bv%7D)
here we know that
![\omega = 2\pi f](https://tex.z-dn.net/?f=%5Comega%20%3D%202%5Cpi%20f)
![\omega = 2\pi(92.2) = 579.3 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%202%5Cpi%2892.2%29%20%3D%20579.3%20rad%2Fs)
so we have
![k = \frac{579.3}{5.69}](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%7B579.3%7D%7B5.69%7D)
![k = 101.8 rad/m](https://tex.z-dn.net/?f=k%20%3D%20101.8%20rad%2Fm)
Part c)
![\omega = 579.3 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%20579.3%20rad%2Fs)
Part d)
here since wave is moving in negative direction so the sign of
must be positive
Answer:
So... for the element of NITROGEN, you already know that the atomic number tells you the number of electrons. That means there are 7 electrons in a nitrogen atom. Looking at the picture, you can see there are two electrons in shell one and five in shell two.