Potassium hydroxide (KOH) and
hydrochloric acid (HCl) react in a beaker. They form potassium chloride (KCl)
and water (H2O). This type of reaction is a double replacement reaction wherein
the two principal reactants exchange after the reaction. The Cl will combine to
the K forming KCl and the H will add to the OH forming H2O.
I need to see the diagram
Other than for the chemical symbol, the electron dot diagram for silicon would be the same as it was for carbon.
The reason for this is because electron dot diagrams are used to represent the electrons in the outermost, or valence, shell of an atom. In a group of the periodic table, all of the elements have the same number of valence shell electrons. This means that all elements belonging to the same group have the same electron dot diagram, except for the symbol of the element that is within the diagram.
Answer:
a) Fi = 85.76 N
b) Fi = 87.8 N
Explanation:
Given:-
- Density of hydraulic oil, ρ = 804 kg/m^3
- The radius of input piston, ri = 0.00861 m
- The radius of output piston, ro = 0.141 m
Find:-
What input force F is needed to support the 23000-N combined weight of a car and the output plunger, when
(a) the bottom surfaces of the piston and plunger are at the same level
(b) the bottom surface of the output plunger is 1.10 m above that of the input plunger?
Solution:-
For part a.
- We see that both plungers are equal levels or there is no pressure due to elevation head. So we are only dealing with static pressure exerted by the hydraulic oil on both plungers to be equal. This part is an application of Pascal's Law:
Pi = Po
Fi / Ai = Fo / Ao
Fi = Ai / Ao * Fo
Fi = (ri/ro)^2 * Fo
Fi = ( 0.00861 / 0.141 )^2 * 23000
Fi = 85.76 N
For part b.
- We see that both plungers are at different levels so there is pressure due to elevation head. So we are only dealing with static pressure exerted by the hydraulic oil on both plungers plus the differential in heads. This part is an application of Bernoulli's Equation:
Pi = Po + ρ*g*h
Where, h = Elevation head = 1.10m
Fi = (ri/ro)^2 * Fo + ρ*g*h*π*ri^2
Fi = 85.76 + (804*9.81*1.1*3.142*0.00861^2)
Fi = 87.8 N
