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KiRa [710]
3 years ago
12

What three factors decide how much gravitational potential energy a body has?

Physics
1 answer:
nikdorinn [45]3 years ago
5 0

Answer:

1. Mass

2. Height

3. Gravitational Force Field

Explanation:

The three factors that decide how much gravitational potential energy a body has are: 1) The mass of the body itself, 2) The relative height at which the body is, because gravitational force varies with height i.e distance away from earth surface. 3) and finally the strength of the gravitational field the body is in.

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The roller coaster from problem #1 then tops a second hill at 15.0 m/s, how high is the second hill?
navik [9.2K]

Answer:

68.5

Explanation:

4 0
2 years ago
3. Specify the wrong sentences.
soldi70 [24.7K]

Answer:

a: false

b: True

c: i dont know

Explanation:

4 0
1 year ago
Which scale has 100 divisions from when the temperature when water freezes to the temperature when water boils
Westkost [7]
The Celsius scale (^{\circ} C).

In the Celsius temperature scale, the temperature at which water freezes is set conventionally at 0^{\circ}C, while the temperature at which the water boils is set at 100^{\circ}C. The Celsius degree is then defined as the unit corresponding to 1/100 of this time interval, between the temperature of freezing and boiling of the water.
8 0
2 years ago
How long does it take a vehicle to reach a velocity of 32 m/s if it accelerates from rest at a rate of 4.2 m/s^2?
Marta_Voda [28]

Answer:

7.62

Explanation:

because you have to divide 32/4.2

and can you do a friend request so i can accept it

4 0
2 years ago
Hanging from a horizontal beam are nine simple pendulums of the following lengths:
LenaWriter [7]

Answer:

Options d and e

Explanation:

The pendulum which will be set in motion are those which their natural frequency is equal to the frequency of oscillation of the beam.

We can get the length of the pendulums likely to oscillate with the formula;

L =\frac{g}{w^{2} }

where g=9.8m/s

         ω= 2rad/s to 4rad/sec

when ω= 2rad/sec

L= \frac{9.8}{2^{2} }

L = 2.45m

when  ω= 4rad/sec

L=\frac{9.8}{4^{2} }

L = 9.8/16

L=0.6125m

L is between 0.6125m and 2.45m.

This means only pendulum lengths in this range will oscillate.Therefore pendulums with length 0.8m and 1.2m will be strongly set in motion.

Have a great day ahead

8 0
3 years ago
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