(V) What are the objectives of the space mission?

Do animals fart and do all animals blink and do animals have the same trait of humans

pantera1 [17]

Uh yes they do fart and blink. Like very living person, and animal. They do have the same traits, as that to humans, but their biology is set up differently. They are stronger and quicker.
I'm not going to state that humans are animals, because I don't agree. Humans are NOT animals!!! But that's my belief, oppose as you like.
I think the best way to answer this question, is to imagine being an animal. Possibly a wild animal. What do you do? How do you find food? Where do you sleep? See, usually humans know how to be disgusted about living in unsanitary and unsafe environments. I mean looking at the traits, they're biology is just set up differently from humans.

I hope this helps.

8 0

4 years ago

Read 2 more answers

Approximately how much of Earth’s water is freshwater?

marishachu [46]

50% water is fresh into Earth

8 0

4 years ago

Read 2 more answers

A car travels along straight line for first half time with a speed of 40 km/h and the second half with a speed of 60km/h find th

Vesna [10]

Answer:

Average speed of car will be 48 km/hr

Explanation:

Let the total distance is 2d

It is given that first half of the distance car travels with a speed of 40 km/hr

So time taken to cover half of the distance $t_1=\frac{d}{40}hr$

Second half of the distance is covered with a 60 km/hr

So time taken to cover second half of the distance $t_2=\frac{d}{60}hr$

So total time to cover 2d distance $t=\frac{d}{60}+\frac{d}{40}=\frac{5d}{120}$

Average speed is the ratio of total distance to total time

So average speed $=\frac{2d}{\frac{5d}{120}}=48km/hr$

So average speed of car will be 48 km/hr

4 0

3 years ago

A spaceship maneuvering near planet zeta is located at r⃗ =(600i^−400j^+200k^)×103km, relative to the planet, and traveling at v

slava [35]

Answer:

The spaceship's position when the engine shuts off = $(708.15 i - 444.1 j + 200 k)*10^3km$

Explanation:

Initial location of spaceship = (600 i - 400 j + 200 k)* $10^3km$ = (600 i - 400 j + 200 k)* $10^6m$

Initial velocity = 9500 i m/s

Acceleration = (40 i - 20 k) $10^3m/s^2$

Time = 35 minute = 35 * 60 = 2100 seconds

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Substituting

$s= (9500 i)*2100+\frac{1}{2}*(40 i - 20 k)*2100^2\\ \\ s=9500*2100 i+20*2100^2i-10*2100^2j\\ \\ s=19.95*10^6i+88.2*10^6i-44.1*10^6j\\ \\ \\s=(108.15i-44.1j)*10^6m$

So final position = $((600 i - 400 j + 200 k)+(108.15i-44.1j))*10^6=(708.15 i - 444.1 j + 200 k)*10^6m$

= $(708.15 i - 444.1 j + 200 k)*10^3km$

The spaceship's position when the engine shuts off = $(708.15 i - 444.1 j + 200 k)*10^3km$

3 0

3 years ago

Read 2 more answers

A balloon rubbed against denim gains a charge of −7.0 µc. what is the electric force between the balloon and the denim when the

zubka84 [21]

The solution for this problem is computed by through this formula, F = kQq / d²Plugging in the given values above, we can now compute for the answer.
F = 8.98755e9N·m²/C² * -(7e-6C)² / (0.03m)² = -489N, the negative sign denotes attraction.

4 0

3 years ago

(V) What are the objectives of the space mission?​

(V) What are the objectives of the space mission?