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andrew11 [14]
4 years ago
5

When the pivot point of a balance is not at the center of mass of the balance, how is the net torque on the balance calculated?

When a force is applied directly to the pivot point of a balance, what is the torque due to that force?
Physics
1 answer:
viktelen [127]4 years ago
8 0

Answer:

Explanation:

Net torque is calculated by multiplying the force with distance from the point of application of force to the point of pivot .

If more than 2 forces are present, then we either subtract the product of forces with their respective distances from pivot point or we add them . It depends on whether they both are present on opposite sides of pivot or on same side of pivot .

When a force is applied directly to the pivot point of balance, then the torque on due that force = 0 (zero) .

It is so because the torque is defined as the product of force and perpendicular distance from the pivot point but here the distance is 0 , therefore torque is zero.

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The temperature of 1.16 kg of water is 34 °C. To cool the water, ice at 0 °C is added to it. The desired final temperature of th
amm1812

Answer:

mass of the ice that will be added is 0.29 kg

Explanation:

Given;

mass of water, M₁ = 1.16 kg

temperature of water, T₁ = 34 °C

final temperature of water-ice system, T₂ =  11 °C

latent heat of fusion for water, L = 33.5 × 10⁴ J/kg

specific heat capacity of water, c = 4186 J/(kg·C°)

Apply the principle of conservation energy;

Heat lost by water when it is cooled from 34 °C to 11 °C  must be equal to heat gained by the ice when it melts.

M₁cΔθ = M₀L + M₀cΔθ

where;

M₁ is mass of water

M₀ is mass of ice

c is specific heat capacity of water

Δθ is change in temperature

L is latent heat of fusion of ice

M₁cΔθ = M₀L + M₀cΔθ

M₁cΔθ = M₀(L + cΔθ)

Mc (T₁ - T₂) = M₀ [L + c(T₂ - 0)]

1.16 x 4186 x (34 - 11) = M₀ [335000 + 4186 x 11]

111682.48 = M₀ (335000 + 46046)

111682.48 = 381046M₀

M₀ = (111682.48) / (381046)

M₀ = 0.29 kg

Therefore, mass of the ice that will be added is 0.29 kg

3 0
3 years ago
Eyes make it possible to see which of the following?
Elza [17]

Answer:

D.  All of the above

Explanation:

Think about it.

Can you see how big or small an object is? Unless in very special cases, the ordinary person can.

Can you see the color of an object? Unless you are color blind (missing color recepticles in your eyes), then yes you can.

Can you see the motion of an object? Unless the object is not moving, or you cannot see, then yes.

~

6 0
3 years ago
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A penny is dropped from the top of a building 290 m high. Ignoring air resistance, if
mel-nik [20]

Answer:

Vf = 75.4 m/s

Explanation:

In order to find the final velocity of the penny when it would hit the ground, we will use the equation of motion. In this particular case the third equation of motion can be used. The third equation of motion is written as follows:

2gh = Vf² - Vi²

where,

Vf = Final Velocity of the penny when it would hit the ground = ?

Vi = Initial Velocity of the penny = 0 m/s (Since, the penny starts from rest)

g = acceleration due to gravity = 9.8 m/s²

h = height of building = 290 m

Therefore,

2(9.8 m/s²)(290 m) = Vf² - (0 m/s)²

Vf = √(5684 m²/s²)

<u>Vf = 75.4 m/s</u>

3 0
3 years ago
In the manufacturing of computer chips, cylinders of silicon are cut into thin wafers that are 3.00 in. in diameter and have a m
Shalnov [3]

Answer: thickness h = 0.014cm

Question: In the manufacturing of computer chips, cylinders of silicon are cut into thin wafers that are 3.30 inches in diameter and have a mass of 1.50 g of silicon. How thick (mm) is each wafer if silicon has a density of 2.33 g/cm 3 ? (The volume of a cylinder is V=πr 2 h )

Explanation:

The volume of a cylinder is

Volume V = πr^2h ....1

The density of a material is

Density D = mass m / volume V

D = m/V ....2

Since m and D are given, we can make V the subject of formula.

V = m/D ....3

From equation 1, we need to derive the thickness h of the cylindrical silicon.

h = V/πr^2 .....4

Substituting equation 3 into 4

h = (m/D)/πr^2 .....5

Given.

mass m = 1.50g

density D = 2.33g/cm^3

radius r = diameter/2 = 3.00in/2 = 7.62/2 cm = 3.81cm

Substituting the given values into the equation

h = (1.5/2.33)/(π ×3.81^2)

thickness h = 0.014cm

3 0
3 years ago
(no links or files) What types of waves are shown in this image?
rewona [7]

Answer:

Absorbed and reflected

Explanation:

B is reflected because you can’t see the red arrow which represents a light that bounces off of it and a aired up sword because you can see it win through the object shown in the picture

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3 years ago
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