Answer:
The direction of the force at A and B is perpendicular to the walls of the container.
The direction of the force at C is down.
The direction of the force in D is up
The direction of the force at E is to the left.
The attached figure shows the forces exerted by the water at points A, B, C, D and E.
Explanation:
The water is in contact with the bowl and with the fish. It exercises at points A, B, C, D and E, but the direction is different from the force.
The fish has a buoyant force on the water and that direction is up. The direction of at point D is up.
The column of water on the fish has a downward force, therefore the direction of the force at point C is down. The water column to the right of the fish has a force to the left, and the direction at point E is to the left.
The water will exert a force on the walls of the container and this force at points A and B is a on the walls of the container.
I believe it’s just a “v” with an arrow above it.
Vx=cos60(4)
x-component of velocity
<span>If you think about it, it makes a right triangle when you combine all the different types of forces together such as v, vx and vy. Then, you can use trigonometry and soh cah toa in order to figure out vx. </span>
I agree with the first person