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liubo4ka [24]
3 years ago
10

The mass of an object on earth is 20 kg what will be the mass of that object on moon? And why? ​

Physics
1 answer:
Alla [95]3 years ago
7 0

Answer:

20kg

Explanation:

Mass is a measure of the amount of matter in an object. The mass of an object, the amount of matter inside it does not change based on location. E.g. Objects do not lose matter when they travel to the moon.

Weight, on the other hand is the downward force you exert on the ground. Weight is calculated by multiplying the mass by the gravitational field strength and changes in different places with different gravitational strength. E.g. The moon's gravitational strength is 1/5 of Earth's so the mass of the object would stay the same but the weight would be only 20% of the weight is had on earth.

Hope this helped!

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The earth has a mass ME = 5.98 · 1024 kg and the moon has a mass MM = 7.36 · 1022 kg. The distance from the center of the earth
ivann1987 [24]

Answer:

2 x 10^20 N

Explanation:

Me = 5.98 x 10^24 kg

Mm = 7.36 x 10^22 kg

r = 3.82 x 10^5 km = 3.82 x 10^8 m

The gravitational force between earth and moon is

F = G Me x Mm / r^2

F = (6.67 x 10^-11 x  5.98 x 10^24 x 7.36 x 10^22) / (3.82 x 10^8 x 3.82 x 10^8)

F = 2 x 10^20 N

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3 years ago
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Answer-

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7 0
3 years ago
which option below best explains why the second law of thermodynamics is not violated when heat flies from a cold freezer and in
Rainbow [258]

Explanation:

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8 0
3 years ago
What engine thrust is required for a rocket of mass 35 kg to leave the launching pad? 3.5 N. 35 N. 351 N. 3,500 N. 35,000 N.
soldi70 [24.7K]

In order for the object to move upward, it needs an upward force
that's at least equal to its own weight.

Weight = (mass) x (gravity) = (35 kg) x (9.8 m/s²) = 343 N.

The engine thrust has to be more than 343 N.

7 0
3 years ago
Consider a steel cable with a diameter of 8.0 mm. Calculatethe stress in the cable when it holds a person weighing 850 N.Report
pishuonlain [190]

Answer:

stress = 16.9 MPa

Explanation:

The stress in the cable can be calculated as:

\text{Stress = }\frac{F}{A}

Where F is the force and A is the area. So, the area can be calculated as:

A=\pi^{}\cdot r^2

Where r is the radius. Since the radius is half the diameter, the radius is 4.0 mm and the area will be equal to:

\begin{gathered} A=3.14(4\operatorname{mm})^2 \\ A=50.24\operatorname{mm}^2 \end{gathered}

Then, replacing the force F by 850 N, and A by 50.24 mm², we get that the stress is equal to:

\text{stress = }\frac{850N}{50.24mm^2}=16.9\text{MPa}

Therefore, the answer is 16.9 MPa

7 0
1 year ago
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