Question

You are sitting on a Ferris wheel moving at a constant speed of 8 m/s. When you are at the bottom of the rotation, what is the normal force of the seat on you if you have a mass of 50 kg and the radius of the Ferris wheel is 10 m

Answer 1

Answer:

40N

Explanation:

Formula for calculating normal force is expressed as:

$F = ma\\since \ a = \frac{v^2}{r} \\F = \frac{mv^2}{r}$

m is the mass of the body = 50kg

v is the velocity of the Ferris wheel = 8m/s

r is the radius of the Ferris wheel

Substitute into the formula:

$F = \frac{50 \times 8}{10}\\ F = \frac{400}{10}\\ F = 40N$

Hence the normal force of the seat is 40N