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11111nata11111 [884]
3 years ago
15

Why do areas north of the artic circle in tje northern hemisphere experience a polar day lasting for several months during summe

r?
A) The region does not experience spin during polar day

B) Earth is at its closest point to the Sun during polar day

C) The regioin is titled towqrd the Sun during polar day

D) Earth's orbit passes below the Sun during polar day
Physics
2 answers:
adell [148]3 years ago
7 0
<span>The regioin is titled towqrd the Sun during polar day.  (C)

(The same exact thing happens in areas south of the Antarctic Circle 
in the southern hemisphere.  The only difference is that the whole thing
is spelled better in the South.)</span>
Tresset [83]3 years ago
3 0

Answer:

C) The region is titled towards the Sun during polar day      

Explanation:

The axis of earth is inclined about 23.5 degrees from the vertical. Due to the tilt, earth experiences different seasons. The sunlight directly falls directly in the equatorial region and slanting beyond the region. In the northern hemisphere, sun is at highest point and it is summers. The sun never sets for the areas north to arctic circle. The northern hemisphere is tilted towards the sun during the polar day.

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Suppose a baseball pitcher throws the ball to his catcher.
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a) Same

b) Same

c) Same

d) Throw the ball takes longer

e) F is larger when the ball is catched

Explanation:

a)

The change in speed of an object is given by:

\Delta v = |v-u|

where

u is the initial velocity of the object

v is the final velocity of the object

The change in speed is basically the magnitude of the change in velocity (because velocity is a vector, while speed is a scalar, so it has no direction).

In this problem:

- In situation 1 (pitcher throwing the ball), the initial velocity is

u = 0 (because the ball starts from rest)

while the final velocity is v, so the change in speed is

\Delta v=|v-0|=|v|

- In situation 2 (catcher receiving the ball), the initial velocity is now

u = v

while the final velocity is now zero (ball coming to rest), so the change in speed is

\Delta v =|0-v|=|-v|

Which means that the two situations have same change in speed.

b)

The change in momentum of an object is given by

\Delta p = m \Delta v

where

m is the mass of the object

\Delta v is the change in velocity

If we want to compare only the magnitude of the change in momentum of the object, then it is given by

|\Delta p|=m|\Delta v|

- In situation 1 (pitcher throwing the ball), the change in momentum is

\Delta p = m|\Delta v|=m|v|=mv

- In situation 2 (catcher receiving the ball), the change in momentum is

\Delta p = m\Delta v = m|-v|=mv

So, the magnitude of the change in momentum is the same (but the direction is opposite)

c)

The impulse exerted on an object is equal to the change in momentum of the object:

I=\Delta p

where

I is the impulse

\Delta p is the change in momentum

As we saw in part b), the change in momentum of the ball in the two situations is the same, therefore the impulse exerted on the ball will also be the same, in magnitude.

However, the direction will be opposite, as the change in momentum has opposite direction in the two situations.

d)

To compare the time of impact in the two situations, we have to look closer into them.

- When the ball is thrown, the hand "moves together" with the ball, from back to ahead in order to give it the necessary push. We can verify therefore that the time is longer in this case.

- When the ball is cacthed, the hand remains more or less "at rest", it  doesn't move much, so the collision lasts much less than the previous situation.

Therefore, we can say that the time of impact is longer when the ball is thrown, compared to when it is catched.

e)

The impulse exerted on an object can also be rewritten as the product between the force applied on the object and the time of impact:

I=F\Delta t

where

I is the impulse

F is the force applied

\Delta t is the time of impact

This can be rewritten as

F=\frac{I}{\Delta t}

In this problem, in the two situations,

- I (the impulse) is the same in both situations

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Therefore, since F is inversely proportional to \Delta t, this means that the force is larger when the ball is catched.

6 0
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Answer:

B

Explanation:

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if you start at point A, then go to point B, and back to point A, the displacement is zero because you started and ended at the same point.

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