If net external force acting on the system is zero, momentum is conserved. That means, initial and final momentum are same → total momentum of the system is zero.
To develop the problem, we require the values concerning the conservation of momentum, specifically as given for collisions.
By definition the conservation of momentum tells us that,
To find the speed at which the arrow impacts the apple we turn to the equation of time, in which,
The linear velocity of an object is given by
Replacing the equation of time we have to,
Velocity two is neglected since there is no velocity of said target before the collision, thus,
Clearing for m_2
Based on the data provided, the impulse of the floor on the ball is 59.4 Ns.
<h3>What is the impulse of the floor on the ball?</h3>
Using the equation of motion to determine the velocity at the end of the fall
Where v is velocity at the end of fall
u is initial velocity = 0
g is acceleration due to gravity = 9.81 m/s^2
h is height = 20
- Taking downward velocity as negative and up as positive
v^2 = 0 + 2 (9.81)(20)
v^2 = 392.4
v = - 19.8 m/s
The velocity, v after bouncing is calculated also:
u = 0
g = 9.81 m/s^2
h = 5.0 m
v^2 = 0 + 2(9.81)(5)
v^2 = 98.1
v = 9.904 m/s
- Impulse = change in momentum
- Impulse = m(v- u)
Impulse = 2.0 × (9.9 -(-19.8)
Impulse = 59.4 Ns
Therefore, the impulse of the floor on the ball is 59.4 Ns.
Learn more about impulse at: brainly.com/question/904448
0.8611 g/cm ^2
Density = mass/ volume
