Answer:
La velocidad del haz de electrones es 1.78x10⁵ m/s. Este valor se obtuvo asumiendo que el campo magnético dado (3500007) estaba en tesla y que la fuerza venía dada en nN.
Explanation:
Podemos encontrar la velocidad del haz de electrones usando la Ley de Lorentz:
(1)
En donde:
F: es la fuerza magnética = 100 nN
q: es el módulo de la carga del electron = 1.6x10⁻¹⁹ C
v: es la velocidad del haz de electrones =?
B: es el campo magnético = 3500007 T
θ: es el ángulo entre el vector velocidad y el campo magnético = 90°
Introduciendo los valores en la ecuación (1) y resolviendo para "v" tenemos:
Este valor se calculó asumiendo que el campo magnético está dado en tesla (no tiene unidades en el enunciado). De igual manera se asumió que la fuerza indicada viene dada en nN.
Entonces, la velocidad del haz de electrones es 1.78x10⁵ m/s.
Espero que te sea de utilidad!
Answer:
A) If the paintball stops completely the magnitude of the change in the paintball’s momentum is 
B) If the paintball bounces off its target and afterward moves in the opposite direction with the same speed, the change in the paintball’s momentum is 
C) A paintball bouncing off your skin in the opposite direction with the same speed hurts more than a paintball exploding upon your skin because of the strength exerted is twice than if it explodes.
Explanation:
Hi
A) We use the formula of momentum 
, so we have 
B) We use the same formula above, then due we have a change of direction at the same speed, therefore the change in the momentum is the double so
.
C) The average strength of the force an object exerts during impact is determined by the amount the object’s momentum changes. therefore
, as we don't have any data about the impact time but we know momentum is twice, time does no matter and strength is twice too.
A is the correct answer !!!
Answer:
Option (e)
Explanation:
If a mass attached to a spring is stretched and released, it follows a simple harmonic motion.
In simple harmonic motion, velocity of the mass will be maximum, kinetic energy is maximum and acceleration is 0 at equilibrium position (at 0 position).
At position +A, mass will have the minimum kinetic energy, zero velocity and maximum acceleration.
Therefore, Option (e) will be the answer.
