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11111nata11111 [884]
3 years ago
15

Why do areas north of the artic circle in tje northern hemisphere experience a polar day lasting for several months during summe

r?
A) The region does not experience spin during polar day

B) Earth is at its closest point to the Sun during polar day

C) The regioin is titled towqrd the Sun during polar day

D) Earth's orbit passes below the Sun during polar day
Physics
2 answers:
adell [148]3 years ago
7 0
<span>The regioin is titled towqrd the Sun during polar day.  (C)

(The same exact thing happens in areas south of the Antarctic Circle 
in the southern hemisphere.  The only difference is that the whole thing
is spelled better in the South.)</span>
Tresset [83]3 years ago
3 0

Answer:

C) The region is titled towards the Sun during polar day      

Explanation:

The axis of earth is inclined about 23.5 degrees from the vertical. Due to the tilt, earth experiences different seasons. The sunlight directly falls directly in the equatorial region and slanting beyond the region. In the northern hemisphere, sun is at highest point and it is summers. The sun never sets for the areas north to arctic circle. The northern hemisphere is tilted towards the sun during the polar day.

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bezimeni [28]

Answer:

205 V

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Explanation:

L = Inductance in Henries, (H)  = 0.500 H

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V_{L} = - IwLsin(wt)

w = 500 rad/s

IwL = 11.0 V

Current:

I = 11.0 V / wL

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I = 0.044 A

Now

V_{R} = IR

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V_{R} = 4.092 V

Deriving formula for voltage across the resistor

The derivative of sin is cos

V_{R} = V_{R} cos (wt)

Putting V_{R} = 4.092 V and w = 500 rad/s

V_{R} = V_{R} cos (wt)

    = (4.092 V) (cos(500 rad/s )t)

So the voltage across the resistor at 2.09 x 10-3 s is which means

t = 2.09 x 10⁻³

V_{R} = (4.092 V) (cos (500 rads/s)(2.09 x 10⁻³s))

    =  (4.092 V) (cos (500 rads/s)(0.00209))

    = (4.092 V) (cos(1.045))

    = (4.092 V)(0.501902)

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V_{R} = 2.05 V

8 0
2 years ago
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Ierofanga [76]

Answer:

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Explanation:

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3 years ago
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3 years ago
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valkas [14]

Answer:

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