All categories

3 years ago

Which graph represents exponential decay?

Mathematics

2 answers:

SashulF [63]3 years ago

4 0

If there is a decrease on y then that’s the answer

nata0808 [166]3 years ago

4 0

Since I can't see the graph, I can't choose exactly, but if:

1. as x rises, y falls

and

2. there is no one slope (there is one curve)

then it represents exponential decay.

Aka. it's a downward woosh.

You might be interested in

Look at picture please !! I really need help thank you !

aksik [14]

I think it’s c if not i’m sorry i got you incorrect but it just makes more since

5 0

3 years ago

Hi guys, can anyone help me with this triple integral? Many thanks:)

Crank

Another triple integral. We're integrating over the interior of the sphere

$x^2+y^2+z^2=2^2$

Let's do the outer integral over z. z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

$y^2=4-x^2-z^2$

x is the inner integral so at this point we conservatively say its zero. That means y goes from $-\sqrt{4-z^2}$ and $+\sqrt{4-z^2}$

Similarly the inner integral x goes between $\pm-\sqrt{4-y^2-z^2}$

So we rewrite the integral

$\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz$

Let's work on the inner one,

$\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz$

There's no z in the integrand, so we treat it as a constant.

$=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}$

So the middle integral is

$\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy$

I gotta go so I'll stop here, sorry.

7 0

3 years ago

Read 2 more answers

Plees 555+555 and 6 541,5-5 410,6

Valentin [98]

Answer:

what is this......................

6 0

3 years ago

Two litters of a particular rodent species have been born; first with two brownhaired and one gray-haired (litter 1) and the oth

maks197457 [2]

Answer:

The probability that the animal chosen is brown-haired is 0.6333.

Step-by-step explanation:

Denote the events as follows:

A : a brown-haired rodent

B : Litter 1

The information provided is:

$P (A|B) =\frac{2}{3}\\\\P(A|B^{c})=\frac{3}{5}$

The probability of selecting any of the two litters is equal, i.e.

$P(B)=P(B^{c})=\frac{1}{2}$

According to the law of total probability:

$P(X)=P(X|Y_{1})P(Y_{1})+P(X|Y_{2})P(Y_{2})+...+P(X|Y_{n})P(Y_{n})$

Compute the total probability of event A as follows:

$P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

$=[\frac{2}{3}\times\frac{1}{2}]+[\frac{3}{5}\times\frac{1}{2}]\\\\=\frac{1}{3}+\frac{3}{10}\\\\=\frac{10+9}{30}\\\\=\frac{19}{30}\\\\=0.6333$

Thus, the probability that the animal chosen is brown-haired is 0.6333.

5 0

3 years ago

PLEASE HELP!!!! Land is often measured in acres. An acre is 4,840 square yards. The Smith family bought a house built on a rect

aleksley [76]

Answer:

1.4385 yards wide

Step-by-step explanation:

First we need to find the total area of the land by multiplying the 2 acres by the size of a single acre in yards...

2 * 4,840 = 9,680 square yards

Since we know that the area of a rectangle is length times width, and we are provided the length of the land. Then we simply need to divide the area of the land by the length provided to get the width of the land

9,680 / 6729 = 1.4385 yards wide

3 0

3 years ago