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9966 [12]
4 years ago
6

What prevents geologist from directly exploring earth’s interior???

Chemistry
2 answers:
maks197457 [2]4 years ago
8 0
<span>the extreme conditions in earth interior</span>
Mashcka [7]4 years ago
7 0
Hey there!

<span>The extreme conditions in the Earth's interior.
4.1.13
</span>
Hope this helps!

~~Cutelion918~~
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State the law of conservation of mass
swat32

Answer:

The law of conservation of mass states that mass can neither be created nor destroyed in a chemical reaction. Thus, the amount of matter cannot change.

Explanation:

8 0
4 years ago
Atmospheric pressure at sea level is 760 mm Hg, and oxygen makes up 20.9% of this air when it is dry. Scientists at the Mt. Wash
Lubov Fominskaja [6]

Answer:

127.28 mmHg

Explanation:

The molar fraction of oxygen in dry air at 760 mmHg is 20.9%. This molar fraction is not affected too much by the height, so it may be taken as a constant. The partial pressure of oxygen may be calculated as:

P_{O_{2}}=y_{O_{2}}*P

So, if the total pressure is 609 mmHg,

P_{O_{2}}=0.209*609=127.28 mmHg.

8 0
3 years ago
ELETE
yKpoI14uk [10]

Answer:

5 L

Explanation:

Use Charles law and rearrange formula

Change C to K

- Hope that helped! Please let me know if you need further explanation.

6 0
4 years ago
Using a molar heat of combustion of hexane (C6H14) –4163 kJ/mol, the mass of hexane required to increase the temperature of 1.76
pshichka [43]

Answer:

7.46 g.

Explanation:

  • Firstly, we need to calculate the amount of heat needed to warm 5.64 kg of water from 21.0°C to 70.0°C using the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by water (Q = ??? J).

m is the mass of water <u><em>(m: we will determine).</em></u>

c is the specific heat capacity of water (c = 4.186 J/g.°C).

ΔT is the temperature difference (final T - initial T) (ΔT =  70.0 °C - 21.0 °C = 49.0 °C).

  • To determine the mass of 1.76 L of water we can use the relation:

mass = density x volume.

density of water = 1000 g/L & V = 1.76 L.

∴ mass = density x volume = (1000 g/L)(1.76 L) = 1760.0 g.

∵ Q = m.c.ΔT

<em>∴ Q = m.c.ΔT </em>= (1760.0 g)(4.186 J/g.°C)(49.0 °C) = 360483.2 J ≅ 360.4832 kJ.

  • As mentioned in the problem the molar heat of combustion of hexane is - 4163.0 kJ/mol.

<em>Using cross multiplication we can get the no. of moles of hexane that are needed to be burned to release 360.4832 kJ:</em>

Combustion of 1.0 mole of methane releases → - 4163.0 kJ.

Combustion of ??? mole of methane releases → - 360.4832 kJ.

∴ The no. of moles of hexane that are needed to be burned to release 360.4832 kJ = (- 360.4832 kJ)(1.0 mol)/(- 4163.0 kJ) = 0.0866 mol.

  • Now, we can get the mass of hexane that must be burned to warm 1.76 L of water from 21.0°C to 70.0°C:

<em>∴ mass = (no. of moles needed)(molar mass of hexane)</em> = (0.0866 mol)(86.18  g/mol) = <em>7.46 g.</em>

5 0
3 years ago
Compare homogeneous and heterogeneous mixtures?
Gemiola [76]
A homogeneous mixture has the same uniform appearance and composition throughout. Many homogeneous mixtures are commonly referred to as solutions. A heterogeneous mixture consists of visibly different substances.
8 0
3 years ago
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