I pretty sure it’s (C) it’s volume will increase.
I hope this helped!
Cysteine and methionine contain sulfur.
Answer:
2.90×10¯⁴M
Explanation:
Step 1:
Data obtained from the question.
Equilibrium constant for the acid , Ka = 3.5×10^–8
concentration of the acetic acid, [CH3COOH] = 2.40M
Concentration of Hydrogen ion, [H+] =..?
Step 2:
The balanced equation for the reaction.
CH3COOH(aq) <=> H+(aq) + CH3COO-(aq)
Step 3:
Determination of the concentration of Hydrogen ion, [H+]. This can be obtained as follow:
Initial concentration:
[CH3COOH] = 2.40M
[H+] = 0
[CH3COO-] = 0
During reaction:
[CH3COOH] = –y
[H+] = +y
[CH3COO-] = +y
At Equilibrium:
[CH3COOH] = 2.40 –y
[H+] = y
[CH3COO-] = y
Now, we can obtain the concentration of Hydrogen ion, H+ as follow:
Ka = [H+] • [CH3COO-] /[CH3COOH]
3.5×10^–8 = y×y/2.40
Cross multiply
y² = 3.5×10^–8 × 2.40
Take the square root of both side
y = √(3.5×10^–8 × 2.40)
y = 2.90×10¯⁴
[H+] = y = 2.90×10¯⁴M
Therefore, the concentration of H+ at equilibrium is 2.90×10¯⁴M
Answer:
Explanation:
The density of a gas can be obtained using the gas ideal equation and the molar mass of the gas.
This is the decution of the final formula:
Now, you just need to substitute values:
- R = 0.08206 atm-liter / k-mol
- d = 32.0 g/mol × 0.9869 atm / [0.08206 atm-liter/k-mol × 273.15K]
- d = 1.4 g/liter (using two significant figures)
As you see, I have not used the 4.8 grams datum. That is because the density of the gases may be calculated from the temperature, pressure and molar mass of the gas, using the ideal gas equation.
Since, you have the mass of gas, you might use this other procedure:
- Volume of 1 mol of gas at STP: about 22.4 liter/mol
- Mass of 1 mol of oxygen gas: 32.0 g/mol (the molar mass)
- number of moles in 4.8 g of oxygen = 4.8 g / 32.0 g/mol = 0.15 mol
- Volume of 0.15 mol of oxygen: 0.15 mol × 22.4 liter/mol = 3.36 liter
- Density = mass / volume = 4.8 g / 3.36 liter = 1.4 g/liter (same result)
Hi
Very easy and
I don't know