To find the product of <span>-2x^3+x-5 and x^3-3x-4, we need to multiply each term in the first polynomial by the second polynomial. (So, x^3 - 3x - 4) times ....
-2x^3 = -2x^6 + 6x^4 + 8x^3
x = x^4 - 3x^2 - 4x
-5 = -5x^3 + 15x + 20
If we add all these together, we get (-2x^6 + 7x^4 + 3x^3 - 3x^2 + 11x + 20)</span>
Answer:
70707mmm = 111nnn
Step-by-step explanation:
Using the basic equation of a line:
y = mx + c;. where m is slope and c is intercept on y axis.
Let mmm = y and nnn = x
(i) 333 = 212121m + c
(ii) 555 = 353535m + c
Making c the subject of the formula in both (i) and (ii)
c = 333 - 212121m = 555 - 353535m
353535m -212121m = 555 - 333
141414m = 222
m = 111/70707
Substitute in (i) above
c = 333 -333 = 0
Hence; y = 111/70707x + c
Finally, mmm = 111/70707 nnn
i.e. 70707mmm = 111nnn
Hope this helps.
Answer:
(1)
Step-by-step explanation:
We will try:
(1) y = 
x => 2 = 2 (seems legit)
(2) y = 4x => 2 = 32 (nope)
(3) y = x - 6 => 2 = 2 (yes but actually no because it is proportional relationship)
(4) y = 
x - 2 => 2 = 2 (like the above)
The sample space has 36 possible pairs from 1,1 1,2 1,3 up to 6,5 and 6,6
(a). Three pairs add to 4 1,3 2,2 and 3,1 so P(4) = 3/36 = 1/12
(b). 6 pairs add to 7 so P(7) = 6/36 = 1/6
(c) 15 pairs add to less than 7 so P(<7) = 15/36 = 5/12
