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3 years ago

Please help right away

Mathematics

1 answer:

Ilya [14]3 years ago

7 0

Answer:

im unsure

Step-by-step explanation:

either 340 or 1152 vehicles

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Can anyone help me with this math question

Lynna [10]

Answer:

89 seats are not being used

Step-by-step explanation:

You subtract the seats being used by teachers

342 - 75 =267

Change 2/3 into a percentage = 66.6%

Find 66.6% of 267= 177.8 (I rounded up to 178)

Then subtract 177.8/178 from 267 to find the amount of seats not being used.

The amount of seats not being used would come down to 89 seats.

I hope this helps!

4 0

3 years ago

What is the value of x in the product of powers below?

Luda [366]

-7
Bbbbbbbbbbbbbbbbbbbbbb

7 0

3 years ago

The airplane in the scale drawing has a wingspan of a feet and a tail span of b feet. If the tailspin in the drawing is 2 inches

xeze [42]

Correct answer is: actual wingspan of airplane is 6 inches.

Solution:-

We are given that wingspan is 'a' feet and tail span is 'b' feet in a scale drawing.

And we are also given that tail span is 2 inches that is b=2 inches and $\frac{a}{b}=3$

Let us plugin the b value in above equation.

$\frac{a}{2}=3$

Multiplying with 2 on both sides.

a=3X2=6 inches.

Hence actual wingspan of airplane is 6 inches.

7 0

3 years ago

Atown uses positive numbers to track increases in population and negative numbers to track decreases in population.

amid [387]

Answer:

Step-by-step explanation:

-60

Step-by-step explanation:

Increase in population is given by positive sign

Change in population in 5 years = -300

Decrease in population is represented by negative sign

Change in population in 1 year = -300\5

= -60

Town's population faces a decrease of 60 residents each year.

4 0

2 years ago

Find the solution set of the following quadratic equations using the quadratic formula.

oksian1 [2.3K]

Answer:

<h3> 1) $x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$ </h3><h3> 2) $x_1=-\dfrac13\,,\quad x_2=-3$ </h3>

Step-by-step explanation:

$x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$

<h3>2)</h3><h3> $3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3$ </h3>

7 0

3 years ago