The time taken by the stone to reach the ground is option A 5.27 seconds.
Given,
The function; y = -16t² + 444
y is the height in feet
t is the time in seconds
A stone from y height is dropped from the edge of a vertical cliff.
We have to find the time taken by the stone to reach the ground;
Here,
y = -16t² + 444
y = 0
Then,
0 = -16t² + 444
16t² = 444
t² = 444/16
t² = 27.75
t = √27.75
t = 5.27 seconds
That is,
The time taken by the stone to reach the ground is option A 5.27 seconds.
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Answer:
jumbo 23 oz, grande 16 oz
Step-by-step explanation:
Use g for grande and j for jumbo
The first equation: 28g + 33j = 1207
The second equation: 28g + 53j = 1667
Subtract the first from the second
28g + 53j = 1667
- 28g + 33j = 1207
Equal 20j = 460
j = 23
Put 23 in for j in either equation and solve for g:
28g + 33(23) = 1207
28g + 759 = 1207
28g = 448
g = 16
Answer: i think its 9 but sorry if I'm wrong I'm only in 4th grade
Step-by-step explanation:
C (235.5mm^2) is the answer
Vote me 1 star but what are they teaching yall