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4 years ago

What is the volume of the cylinder below radius 7 height 4

Mathematics

2 answers:

steposvetlana [31]4 years ago

7 0

The formula of a volume of a cylinder:

$V=\pi r^2H$

We have r = 7 and H = 4. Substitute:

$V=\pi(7^2)(4)=\pi(49)(4)=196\pi\ u^3$

Veseljchak [2.6K]4 years ago

6 0

V = pi * r^2 *h

where r is the radius and h is the height of the cylinder

V = pi * 7^2 *4

V = pi* 49*4

pi is approximated by 3.14 or 22/7

V = 22/7 * 49 * 4

V = 616 units ^3

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$\large\boxed{(x-2)^2+(y-1)^2=34}$

Step-by-step explanation:

The equation of a circle in standard form:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1$

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points (2, 1) and (5, -4):

$r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}$

Finally we have:

$(x-2)^2+(y-1)^2=(\sqrt{34})^2$

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