Write an equation in slope-intercept form that has m = 5/4 through (-4,-3)

Mathematics

1 answer:

timama [110]3 years ago

4 0

Answer:

y=5/4x + 2

Step-by-step explanation:

Ok so in the point (-4,-3) -4 is x and -3 is y. Now, since you have the slope, 5/4, you can put it into an equation. -3= 5/4(-4) + b. When you multiply 5/4 x -4 you get -3=-5 + b so then add 5 to both sides to get rid of it and you have 2=b. And your equation would be y=5/4x + 2

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How would I start to solve number 15? Would I use distributive property?

natita [175]

$-5-x=2x-(4x+6)$

Using the distributive property is the correct first step. $(4x+6)$ is being multiplied by -1, so distributing gives

$-5-x=2x+(-4x-6)$
$-5-x=2x+((-4x)+(-6))$

Now, using the associative property of addition, you get

$-5-x=(2x+(-4x))+(-6)$
$-5-x=(2x-4x)-6$

Simplify the right hand side:

$-5-x=-2x-6$

Add 5 and $2x$ to both sides.

$(2x+5)-5-x=(2x+5)-2x-6$

On the left side, use the associative property. On the right, commutativity and associativity:

$2x+(5-5)-x=5+(2x-2x)-6$

Simplify.

$2x-x=-1$
$x=-1$