You can represent an odd integer whith the expression 2n+1, where n is any integer . Write and solve an equation to find three c
onsecutive odd that have a sum of 63
1 answer:
Any odd number can be expressed by 2n+1.
For example,
2n+1=111
2n=110
n=110/2=55
means that 111 is 2n+1 for n=55
Thus if an odd number is 2a+1, the next few numbers are as follows:
2a+1, 2a+2, 2a+3, 2a+4, 2a+5
So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.
Back to our problem:
three consecutive odd numbers whose sum is 63 are:
(2n+1)+(2n+3)+(2n+5)=63
6n+9=63
6n=63-9=54
n=54/6=9
2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23
Answer: 19, 21, 23
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Answer:
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Step-by-step explanation:
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Answer:
CA = 5
Step-by-step explanation:
Since the sides are 3 and 4, we recognize this as a 3:4:5 right triangle, with CA = 5. Using the Pythagorean theorem confirms this:
CA² = AB² +BC²
CA² = 3² +4² = 9 +16 = 25
CA = √25
CA = 5
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Answer:
Answer is $10,144.50
Step-by-step explanation:
15% of 220 =33
220- 33 = 187
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187+15.89=202.89
202.89 x 50 =10,144.50