Help me with this plz

Mathematics

2 answers:

Paul [167]3 years ago

5 0

1) 7000+300+10+3
2) 900,000+90,000+400+40+6
3) 600+80+2
4)30,000+7000+900+10+1
5)3,000,000+900,000+40,000+1,000+400+70+7
6)8000+400+70+4
7)700+70+2
8)30,000+7000+200+80+2
9)700,000+30,000+5,000+800+10+1
10)40,000+6000+400+40+9
11)5000+8000+70+2
12)5,000,000+700,000+50,000+8,000+900+40+5
13)5,000,000+900,000+90,000+8,000+800+90+0
14)300+70+7
15)300,000+20,000+3,000+200+40+8

olasank [31]3 years ago

5 0

1) 7,000+300+10+3
2)900,000+90,000+7,000+400+40+6
3)600+80+2
4)30,000+7,000+900+10+1
5)3,000,000+900,000+40,000+1,000+400+70+7
First few questions answered ;)

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NEED HELP FAST PLEASE Evaluate the limit. a.4 c.1 b.2 d.limit does not exist

BlackZzzverrR [31]

We have the following limit:
(8n2 + 5n + 2) / (3 + 2n)
Evaluating for n = inf we have:
(8 (inf) 2 + 5 (inf) + 2) / (3 + 2 (inf))
(inf) / (inf)
We observe that we have an indetermination, which we must resolve.
Applying L'hopital we have:
(8n2 + 5n + 2) '/ (3 + 2n)'
(16n + 5) / (2)
Evaluating again for n = inf:
(16 (inf) + 5) / (2) = inf
Therefore, the limit tends to infinity.
Answer:
d.limit does not exist

7 0

3 years ago

Heidi earns $11.50 per hour plus a bonus of $105 for the week. Her goal is to earn $650 for the week. Which equation

Stells [14]

Answer:

48 hours

Step-by-step explanation:

$650 - $105 = $545

$545 ÷ $11.50 = 47.39 = 48 hours (Rounded)

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3 years ago

Katrina randomly selected 64 students out of her school of 400 students and found that 40 of them want school to start at a late

SashulF [63]

- The sample size is 64.

- The point estimate of the population proportion is 0.625.

-The margin of error is approximately 16%.

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3 years ago

Read 2 more answers

help with number 2 please i have no idea how to do this. it would be very helpful if you can show the steps

zloy xaker [14]

So in this case, we have to replace the known value.
y=3
y=-2x+3

3=-2x+3

Then we leave our unknown value alone.
$\frac{3-3}{2}$ = x

In this case, our x value would be 0.

We check it...
3=-2(0)+3
3=0+3
3=3

So y=3 x=0

For the second one we have...
y=3x+2
y=-3x-4

For this we substitute the y in any of the equation...
3x+2=-3x-4

We move the unknown values to one side and the ones without unlown values to the other side...
3x+3x=-4-2

Then we solve
6x=-6

Then we leave the unknown value alone.
x= $\frac{-6}{6}$

Then solve for x.
x= -1

Then for our y value we return to one of the original equations and substitute the x value.
y=3x+2
y=3(-1)+2
y=-3+2
y=-1

y=-3x-4
y=-3(-1)-4
y=3-4
y=-1

So in this case we got that x= -1 and y= -1

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4 years ago

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3 years ago