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AleksAgata [21]
3 years ago
9

Find the arc length of arc CDE(hint don’t use 40degrees) A. 8pi cm B. 16pi cm C. 10pi cm

Mathematics
2 answers:
Ivanshal [37]3 years ago
6 0
C the answer is c i think
sdas [7]3 years ago
4 0
Answer:

C


I hope you get it right!!!!!!
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If f(x)=2x+sinx and the function g is the inverse of f then g'(2)=
Alexxx [7]
\bf f(x)=y=2x+sin(x)
\\\\\\
inverse\implies x=2y+sin(y)\leftarrow f^{-1}(x)\leftarrow g(x)
\\\\\\
\textit{now, the "y" in the inverse, is really just g(x)}
\\\\\\
\textit{so, we can write it as }x=2g(x)+sin[g(x)]\\\\
-----------------------------\\\\

\bf \textit{let's use implicit differentiation}\\\\
1=2\cfrac{dg(x)}{dx}+cos[g(x)]\cdot \cfrac{dg(x)}{dx}\impliedby \textit{common factor}
\\\\\\
1=\cfrac{dg(x)}{dx}[2+cos[g(x)]]\implies \cfrac{1}{[2+cos[g(x)]]}=\cfrac{dg(x)}{dx}=g'(x)\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}

now, if we just knew what g(2)  is, we'd be golden, however, we dunno

BUT, recall, g(x) is the inverse of f(x), meaning, all domain for f(x) is really the range of g(x) and, the range for f(x), is the domain for g(x)

for inverse expressions, the domain and range is the same as the original, just switched over

so, g(2) = some range value
that  means if we use that value in f(x),   f( some range value) = 2

so... in short, instead of getting the range from g(2), let's get the domain of f(x) IF the range is 2

thus    2 = 2x+sin(x)

\bf 2=2x+sin(x)\implies 0=2x+sin(x)-2
\\\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}\implies g'(2)=\cfrac{1}{2+cos[2x+sin(x)-2]}

hmmm I was looking for some constant value... but hmm, not sure there is one, so I think that'd be it
5 0
3 years ago
Walter owns 60 books now. He plans to buy 10 books every month. Which recursive formula gives the number of books Walter will ha
Mandarinka [93]
E.) next = now × 10, starting at 60.
3 0
3 years ago
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Please can you help me I'll mark brainiest please and it's being timed!!
Scrat [10]

Answer:

Step-by-step explanation:

The point ( -2 , 3) lies in the 2nd quadrant

Point are generally in the form (x , y). The point you need to plot is ( -2 , 3) which means the value of x = -2 and the value of y = 3.

I have attached an image you can check it out.

8 0
3 years ago
What is the slope-intercept form of them equation of a line that passes through (5, -4) and has a slope of 3/4?
EastWind [94]

C is correct answer, passes through (5,-1) and also has slope of 3/4



5 0
3 years ago
If 2(x + 3) + 7x = 3(x - 2) - 9, then x = ?
Fudgin [204]

Answer:

x=− 7 over 2 =−3.500

Hope this helps!

5 0
3 years ago
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