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Anvisha [2.4K]
3 years ago
12

Element X decays radioactively with a half life of 6 minutes. If there are 790 grams of Element X, how long, to the nearest tent

h of a minute, would it take the element to decay to 35 grams?
Mathematics
1 answer:
frosja888 [35]3 years ago
7 0

Answer:

It takes 27 minutes for the element to decay to 35 grams

Step-by-step explanation:

Given:

Initial amount  =  790 grams

Final amount =  35 grams

Half life =  6 minutes

To find:

Time taken for the element to reduce into 35 grams  = ?

Solutions

Time taken = half life  \times \frac{ log(\frac{ initial amount}{final amount})}{log(2)}

On substituting the values given, Time taken  

= 6 \times \frac{log(\frac{790}{35})}{log(2)}

= 6 \times \frac{log(22.57)}{log(2)}

= 6 \times 4.496

= 26.97

= 27 minutes

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The local bike shop sells a bike and accessories package for $320 if the bike is worth 7 times more than the accessories,how muc
sdas [7]
So, bike=b and accessories=a.

b+a=320

Since the bike is worth 7 times more than the accessories, the b would turn into 7a (because 7 times the cost of accessories is the cost of the bike).

The equation would now turn into 7a+a=320.

Solve for a.

7a+a=320
8a=320
a=40

Now that you know the cost of the accessories, you multiply that 40
by 7 to get the cost of the bike.

40(7)
280

The cost of the bike is $280.
The cost of the accessories are/is $40.
6 0
3 years ago
Suppose a shoe factory produces both low-grade and high-grade shoes. The factory produces at least twice as many low-grade as hi
umka2103 [35]

Answer:

The factory should produce 166 pairs of high-grade shoes and 364 pairs of low-grade shoes for maximum profit

Step-by-step explanation:

The given parameters for the shoe production are;

The number of low grade shoes the factory produces ≥ 2 × The number of high-grade shoes produced by the factory

The maximum number of shoes the factory can produce = 500 pairs of shoes

The number of high-grade shoes the dealer calls for daily ≥ 100 pairs

The profit made per pair of high-grade shoed = Birr 2.00

The profit made per of low-grade shoes = Birr 1.00

Let 'H', represent the number of high grade shoes the factory produces and let 'L' represent he number of low-grade shoes the factory produces, we have;

L ≥ 2·H...(1)

L + H ≤ 500...(2)

H ≥ 100...(3)

Total profit, P = 2·H + L

From inequalities (1) and (2), we have;

3·H ≤ 500

H ≤ 500/3 ≈ 166

The maximum number of high-grade shoes that can be produced, H ≤ 166

Therefore, for maximum profit, the factory should produce the maximum number of high-grade shoe pairs, H = 166 pairs

The number of pairs of low grade shoes the factory should produce, L = 500 - 166 = 334 pairs

The maximum profit, P = 2 × 166 + 1 × 364 = 696

6 1
3 years ago
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LenKa [72]

Answer:

buena suerte ojala encuentres

7 0
3 years ago
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State the domain of the numbers displayed in column x and column y. x y
ella [17]

We can not really tell in this question as you dont know the equation that is being used for the domain and range relationship but overall one should know that:

The set of values of the independent variable(s) for which a function or relation is defined as the domain of a function. Typically, this is the set of x-values that give rise to real y-values.

The range of a function is the complete set of all possible resulting values of the dependent variable (y, usually), after we have substituted the domain.


5 0
3 years ago
PRE CALCULUS
Mumz [18]
Start with the parent function f(x) = x³

Notice the function f(x) = (x - 4)³ that a value '4' is subtracted from 'x' ⇒ This means the function f(x) is translated four units to the right.

Then the function f(x) = ¹/₂ (x - 4)³, the function (x - 4)³ is halved vertically ⇒ Half the y-coordinate

Then the function f(x) = ¹/₂ (x - 4)³ + 5 that a value '5' is added to ¹/₂ (x - 4)³ ⇒ This means the function f(x)  is translated five units up

So the order of transformation that is happening to f(x) = x³ is translation four units to the right, half the y-coordinate, then translate 5 units up.

3 0
3 years ago
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