Answer:

Step-by-step explanation:
Question 1
The point-slope formula for a straight line is
y – y₁ = m(x – x₁)
x₁ = 3; y₁ = -5; m = -4
Substitute the values

The diagram shows the graph of equation 1 (red) with slope -4 passing through (3,-5).
Question 2
x₁ = -1; y₁ = 8; m = 1
Substitute the values

The diagram shows the graph of equation 2 (green) with slope 1 passing through (-1,8).
Answer: none of them is right, did you meant maximum 4 and minimum 2?
Step-by-step explanation: cos x gets values between 1 and -1.
If you add 3 you get values between 4 and 2.
Answer:
12:50 PM.
Step-by-step explanation:
We have been given that Craig’s school has 4 lessons in the morning and lesson 1 starts at 8:35. Each lesson is 60 minutes long. There is a break of 15 minutes between lesson 2 and 3.
We can see that lesson 1 will end at 9:35 AM and second lesson will end at 10:35 AM.
We have been also given that there is a break for 15 minutes between lesson 2 and 3. So third lesson will start at 10:50 AM as lunch break will end at 10:50 AM.
Third lesson will end 60 minutes after 10:50 AM that is 11:50 AM and fourth lesson will end 60 minutes after 11:50 AM that is 12:50 PM.
Therefore, 4th lesson will end at 12:50 PM.
Answer:
<h2><em><u>2a</u></em></h2>
Step-by-step explanation:
(a+b-c)-(b-a-c)
= a + b - c - b + a + c
= a + a + b - b - c + c
= <em><u>2a (Ans)</u></em>
Answer:
y = -3/4x - 6
Step-by-step explanation:
Use y-intercept (0, -6) and slope -3/4 and put into y=mx+b form to solve for b
Remember that m is also known as slope!
-6=(-3/4 * 0) + b
b= -6
y= -3/4x - 6