4πr2
= 4×π×42
= 64π
= 201.06192982975 inches2
The answer should be the last one
Answer:
a) Q(-2,1) is false
b) Q(-5,2) is false
c)Q(3,8) is true
d)Q(9,10) is true
Step-by-step explanation:
Given data is
is predicate that
then
. where
are rational numbers.
a)
when 
Here
that is
satisfied. Then

this is wrong. since 
That is 
Thus
is false.
b)
Assume
.
That is 
Here
that is
this condition is satisfied.
Then

this is not true. since
.
This is similar to the truth value of part (a).
Since in both
satisfied and
for both the points.
c)
if
that is
and
Here
this satisfies the condition
.
Then 
This also satisfies the condition
.
Hence
exists and it is true.
d)
Assume 
Here
satisfies the condition 
Then 
satisfies the condition
.
Thus,
point exists and it is true. This satisfies the same values as in part (c)
Answer:
(6,-2.5)
Step-by-step explanation:
The formula for the midpoint between two points is:

Now we substitute
We have than (9, -1) is
and (3, - 4) is 
So:

So, we have:

<h2>(6,-2.5)</h2><h2 />
I can do a graphic explanation if you want.
Because the number is even, then the number of possible combinations will be: 110/2 = 55 let's consider a simpler example, the number: 10, then we have: 10+0, 9+1, 8+2, 7+3, 6+4, which is equal to 10/2 =5 combinations. Note: We are not considering permutations between the elements of the sum therefore 10+0, 0+10 counts as one combination.