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Allushta [10]
4 years ago
12

How do I multiply fractions without a whole number

Mathematics
2 answers:
Slav-nsk [51]4 years ago
6 0
U need to cross multiply
lys-0071 [83]4 years ago
3 0
Cross multiply put a number over a number and times top by bottom
You might be interested in
Solve. 8 – 3x – x = 12 <br> x =?
poizon [28]
You have to isolate x. First you start off by adding the like terms which is -3x and -x. By adding them you get -4x.

8 - 4x = 12

Then you subtract 8 on both sides since it is positive to isolate x.
-4x = 4

Then you divide -4 by both sides and get x=4/-4

4/-4 is simplified to -1 so the answer is x= -1
3 0
3 years ago
The formula K=C+273.15 converts temperatures from Celsius C to Kelvin K.
Vanyuwa [196]
A. C= K-273.15
b. 300= C+273.15
300-273.15= C
26.85=C
4 0
3 years ago
Can someone help me with this? its solving systems by substitution
yKpoI14uk [10]
Answer: x = 1 and y = 2

Given:
y = -3x + 5
5x - 4y = -3

Since we are given y, let’s sub it in the second equation.

5x - 4(-3x + 5) = -3
5x + 12x - 20 = -3
17x = 17
x = 1

After finding x, we can now find y.

5(1) - 4y = -3
-4y = -8
y = 2

Checking:

y = -3x + 5
2 = -3(1) + 5
2 = 2


5x - 4y = -3
5(1) - 4(2) = -3
-3 = -3
8 0
3 years ago
Please help!!! I’m so confused on how to solve this!
-Dominant- [34]

Let's first write the equation given

x²+6x-13=0

They have told us to use "Completing the square" method.

So we need write x²+6x-13 as a whole square.

x²+6x-13=0

x²+(2*3*x)-9-4 = 0

x²+(2*3*x)-3²=4

Now we can write the LHS as:

(x - 3)²=2²

Hence,

x-3 can either be 2 or -2

Now,

x - 3=2

x=5

Or,

x - 3=-2

x=1

Therefore now we know that x can either be 1 or  5. So the correct answer is  Option B.

8 0
4 years ago
Read 2 more answers
How would you solve this? help.
Eddi Din [679]

Answer:

<em>Center: (3,3)</em>

<em>Radius: </em>2\sqrt{5}<em />

Step-by-step explanation:

<u>Midpoint and Distance Between two Points</u>

Given two points A(x1,y1) and B(x2,y2), the midpoint M(xm,ym) between A and B has the following coordinates:

\displaystyle x_m=\frac{x_1+x_2}{2}

\displaystyle y_m=\frac{y_1+y_2}{2}

The distance between both points is given by:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Point (5,7) is the center of circle A, and point (1,-1) is the center of the circle B. Given both points belong to circle C, the center of C must be the midpoint from A to B:

\displaystyle x_m=\frac{5+1}{2}=\frac{6}{2}=3

\displaystyle y_m=\frac{7-1}{2}=\frac{6}{2}=3

Center of circle C: (3,3)

The radius of C is half the distance between A and B:

d=\sqrt{(1-5)^2+(-1-7)^2}

d=\sqrt{16+64}=\sqrt{80}=\sqrt{16*5}=4\sqrt{5}

The radius of C is d/2:

r =4\sqrt{5}/2 = 2\sqrt{5}

Center: (3,3)

Radius: 2\sqrt{5}

8 0
3 years ago
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