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3 years ago

2. Which is equal to log6?

1 answer:

3 0

<span>The Value of Log(6) = 0.77815125 the values given in different forms of Log are independent from each other and thus do not match any of the other listed values.</span>

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Please help with 1 Math question!!!

musickatia [10]

For this case we must solve the following quadratic equation:

$x ^ 2-5x-8 = 0$

We use the quadratic formula to find the solutions:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Where:

$a = 1\\b = -5\\c = -8$

Substituting we have:

$x = \frac {- (- 5) \pm \sqrt {(- 5) ^ 2-4 (1) (- 8)}} {2 (1)}\\x = \frac {5 \pm \sqrt {25 + 32}} {2}\\x = \frac {5 \pm \sqrt {57}} {2}$

In this way we have two roots:

$x_ {1} = \frac {5+ \sqrt {57}} {2}\\x_ {2} = \frac {5- \sqrt {57}} {2}$

Answer:

$x_ {1} = \frac {5+ \sqrt {57}} {2}\\x_ {2} = \frac {5- \sqrt {57}} {2}$

6 0

3 years ago

Which is a valid prediction about the continuous function f(x)?

goblinko [34]

I believe the answer is C. third choice

<span>f(x) ≥ 0 over the interval [–1, 1].</span>

6 0

3 years ago

Read 2 more answers

The answer choices are -3, 3/2, 3, and -12/5.<br> thanks in advance!! :)

BabaBlast [244]

Answer:

Step-by-step explanation:

$\frac{x}{2(x+1)}$ = $\frac{-2x}{4(x+1)}$ + $\frac{2x-3}{x+1}$ ( x ≠ - 1 )

$\frac{x}{2(x+1)}$ - $\frac{2x-3}{x+1}$ + $\frac{x}{2(x+1)}$ = 0

$\frac{2x-3}{x+1}$ - $\frac{x}{(x+1)}$ = 0

$\frac{x-3}{x+1}$ = 0 ⇒ <em>x = 3</em>

8 0

3 years ago

6(w – 2) + 2 = 2(3w - 5)

galben [10]

Answer:

Infinite Solutions

Step-by-step explanation:

7 0

3 years ago

Use the discriminant, b2 - 4ac, to determine which equation has complex solutions.

ruslelena [56]

Using the discriminant, the quadratic equation that has complex solutions is given by:

x² + 2x + 5 = 0.

<h3>What is the discriminant of a quadratic equation and how does it influence the solutions?</h3>

A quadratic equation is modeled by:

y = ax² + bx + c

The discriminant is:

$\Delta = b^2 - 4ac$

The solutions are as follows:

If $\mathbf{\Delta > 0}$ , it has 2 real solutions.

If $\mathbf{\Delta = 0}$ , it has 1 real solutions.

If $\mathbf{\Delta < 0}$ , it has 2 complex solutions.

In this problem, we want a negative discriminant, hence the equation is:

x² + 2x + 5 = 0.

As the coefficients are a = 1, b = 2, c = 5, hence:

$\Delta = 2^2 - 4(1)(5) = 4 - 20 = -16$

More can be learned about the discriminant of quadratic functions at brainly.com/question/19776811

#SPJ1

3 0

1 year ago