Let X be the number of lightning strikes in a year at the top of particular mountain.
X follows Poisson distribution with mean μ = 3.8
We have to find here the probability that in randomly selected year the number of lightning strikes is 0
The Poisson probability is given by,
P(X=k) = 
Here we have X=0, mean =3.8
Hence probability that X=0 is given by
P(X=0) = 
P(X=0) = 
P(X=0) = 0.0224
The probability that in a randomly selected year, the number of lightning strikes is 0 is 0.0224
X + (x + 10) = 154
2 x + 10 = 154
2 x = 154-10 = 144
x = 72 (ans)
Not sure if it’s right
Answer:
C f=9
Step-by-step explanation:
isolate f on one side so you subtract 5 from both sides to get 3f=27 and then divide by 3 on each side to get f=9
7/8*8/9 = (7*8)/(8*9)
Since we have an 8 both above and below, we can erase it, and so the answer is 7/9
Answer:
A. −4 + 4 = 0
Step-by-step explanation:
-4 + 4 = 0
4 - 4 = 0
So option A will be the answer