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soldier1979 [14.2K]
4 years ago
13

What is the simplified form of the expression?

Mathematics
2 answers:
BaLLatris [955]4 years ago
7 0
The simplified form of the expression is 729x^33
trasher [3.6K]4 years ago
3 0
The answer would be 729x^3^3
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3 x (4 + 7) - * 4) + (7)
Zarrin [17]

Answer:

22 assuming the * was a mistake im not sure if u meant the * if u did mean in what does it mean

Step-by-step explanation:

4 0
3 years ago
The circumference of a circle of diameter 3,5 cm is 11 cm. What is the circumference of a circle of diameter 42 cm? Answer ... c
andreyandreev [35.5K]

Answer:

131.95 cm

Step-by-step explanation:

The Formula for the circumference of a circle is πd where d is the diameter. Therefore you simply multiply 42 with PI to get the circumference

5 0
3 years ago
How to solve -4(-4+x)>56
irga5000 [103]

Answer:

x <-10

Step-by-step explanation:

-4(-4+x)>56

Divide each side by -4, remembering to flip the inequality

-4/-4(-4+x)<56/-4

-4+x < -14

Add 4 to each side

-4+4+x < -14+4

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6 0
3 years ago
5. A negative number squared decreased by 7 times that number is 30. Find<br> the number
Schach [20]

Answer:

7

Step-by-step explanation:

8 0
3 years ago
Using the Divergence Theorem, find the outward flux of F across the boundary of the region D. F = 2xy2i + 2x2yj + 2xyk ; D: the
Zarrin [17]

Answer:

Flux = 16π

Step-by-step explanation:

The outward flux of F across the solid cylinder and z = 0 is

∫∫F*ds  = ∫∫∫ DivF*dv

F = 2xy²i   +  2x²yj + 2xyk

DivF  =  D/dx (2xy²)  +   D/dy (2x²y )

DivF  =  2y²  +  2x²

In cylindrical coordinates   dV = rdrdθdz and as z = 0 the region is a surface ds = rdrdθ

Parametryzing the surface equation

x = rcosθ        y =  r sinθ      and z = z

Div F  = 2r²sin²θ  + 2r²cos²θ

∫∫∫ DivF*dv  =  ∫∫ [2r²sin²θ  + 2r²cos²θ]* rdrdθ

∫∫ 2r² [sin²θ  + cos²θ]* rdrdθdz   ⇒  ∫∫ 2r³ drdθ

Integration limits

0 < r < 2          0 < θ < 2π

2∫₀² r³ ∫dθ

(2/4)(2)⁴ 2π

Flux = 16π

5 0
3 years ago
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