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antoniya [11.8K]
3 years ago
14

Complete the square. Can you show how please, I'm lost X^2 + 20x - 4y + 100 = 0

Mathematics
2 answers:
seraphim [82]3 years ago
7 0
Ignore -4y for now, put of to side

so what you do

(x^2+20x+100)-4y=0
take 1/2 of 20 and squaer it to get 100
neat, 100 is already there
so then factor perefect square
(x+10)²-4y=0
that is how you complete the square
if we had 4y² instead of 4y we could get
(x+10-2y)(x+10+2y)=0 but we don't


completed square is
(x+10)²-4y=0
n200080 [17]3 years ago
4 0
Ignore the -4y term for now. Only focus on x^2+20x+100. This can be factored to (x+10)^2. Notice how expanding it out gives

(x+10)^2 = (x+10)(x+10) 
(x+10)^2 = x(x+10) + 10(x+10)
(x+10)^2 = x^2+10x + 10x + 100
(x+10)^2 = x^2 + 20x + 100

So this means
x^2+20x-4y+100 = 0
turns into
(x+10)^2 - 4y = 0
after we factor

The second equation listed above implies that we have a parabola because we can solve for y to get
-4y = -(x+10)^2
y = (1/4)(x+10)^2
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a sequence U1, U2,U3...... is defined by the relation U_{n +1} = 2U_n +5. if U1 =2, find U2​ and U3

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Step-by-step explanation:

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