Answer:
The answer is -12
Step-by-step explanation:
2xy + 3x + 4x + 3 if x = 5 and y = -5
Now,
2xy + 3x + 4x + 3
2(5)(-5) + 3(5) + 4(5) + 3
-50 + 15 + 20 + 3
38 - 50 = -12
Thus, The answer is -12
<u>-</u><u>TheUnknownScientist</u>
Answer: 10 is your answer bud ❤
Answer:
See explanation
Step-by-step explanation:
3(x + 4) + 2 = 2 + 5(x – 4)
Step 1: distributive property
3(x + 4) + 2 = 2 + 5(x – 4)
3x + 12 + 2 = 2 + 5x - 20
Step 2: collect like terms
3x + 12 + 2 = 2 + 5x - 20
3x + 14 = 5x - 18
Step 3: Addition property of equality
3x + 14 = 5x - 18
3x + 14 + 18 = 5x - 18 + 18
3x + 32 = 5x
Step 4: subtraction property of equality
3x + 32 - 3x = 5x - 3x
32 = 2x
Step 5: division property of equality
32 = 2x
32/2 = 2x/2
16 = x
x = 16
Answer:
Volume of the cylinder = 
Step-by-step explanation:
Height of the Cylinder(h)=5 units
Radius(r)=2 units
Volume of a cylinder=
Putting the values in the formula;
Volume of the cylinder 
As,
Volume of the cylinder=
The Volume of the cylinder is 
Answer:
The center of the circle is:
Thus, option (2) is true.
Step-by-step explanation:
The circle equation is given by

here,
Given the equation



comparing with the circle equation

Therefore, the center of the circle is:
Thus, option (2) is true.