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olga2289 [7]
3 years ago
12

Can someone help me with this problem! My smoll brain cant figure it out

Mathematics
1 answer:
kozerog [31]3 years ago
3 0
How can she have 11 pens and 18 of them be red if the question is written correctly then it is about 163.64
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A room has a rectangular floor that is 15 feet by 21 feet. What is the area of the floor in square yards ? ​
Soloha48 [4]

Answer:

Hey There!

Let's solve...

Here it is a rectangular floor with length =21 cm and width =15cm

So

area = l \times w \\  = 21 \times 15 \\  = 315 {ft}^{2} \\  \\

So now We need to convert it to yards square

315ft^{2} \times  \frac{ {1yd}^{2} }{ {9ft}^{2} } \\  \\  =  \cancel{315ft^{2}}  \: ^{35}  \times  \frac{ {1yd}^{2} }{ \cancel{9 {ft}^{2} }}  \\  \\  = 35 {yd}^{2}

So how this 9 ft^2 came??

Let's know

ft \to \: yards \\  \\ 3ft = 1yd \\  \\  {3ft}^{2} =  {1yd}^{2}  \\  \\  \boxed{ {9ft}^{2} =  {1yd}^{2}}

<h2>I hope it is helpful to you...</h2><h3>Cheers!_______</h3>
8 0
2 years ago
Read 2 more answers
Match the following expression 12(x-3)+18=4(2x-3) with the number of solutions below.
vfiekz [6]
12(x-3) + 18 = 4(2x-3)

12x-36+18 = 8x-12

12x -18 = 8x-12

12x-8x = -12 + 18

4x = 6

x = 6/4 or 3/2

one solution A

4 0
3 years ago
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Two different formulations of an oxygenated motor fuel are being tested to study their road octanenumbers. The variance of road
Lyrx [107]

Answer:chomai

Step-by-step explanation:chomai

3 0
2 years ago
4(x+3)^2=-100. Solve using the square root property.
Leya [2.2K]

Answer:

x= 7, -13

Step-by-step explanation:

5 0
2 years ago
At a certain clinic, 2 percent of all pap smears show signs of abnormality. (a) What is the expected number of pap smears that m
eimsori [14]

Answer:

The expected amount of pap smears that must be inspected before the first abnormal one is found is 50

Step-by-step explanation:

If 2 percent of all pap smears show signs of abnormality, then the probability that a pap smear is abnormal is 0.02.

Let X be the amount of pap smears needed before the first abnormal case is found. X has geometric ditribution with parameter p = 0.02. The mean of X, in other words, the expected amount of cases that must be inspected before the first abnormal one appears, is 1/p = 1/0.02 = 50.

6 0
3 years ago
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