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Anestetic [448]
3 years ago
6

If 8% of all cell phones are defective, and you have a random sample group of 100 Samsung Galaxy Vills,

Mathematics
1 answer:
Sati [7]3 years ago
5 0

Answer:

Mean = 8

Variance = 7.36

Standard Deviation = 2.7129

Step-by-step explanation:

This is a binomial distribution with parameters, n and p.

Where

n is sample size (given as 100)

p is the probability of success, or probability of defective (given as 8% or 0.08)

The mean, variance, standard deviation formula for binomial distribution is shown below:

Mean = np

Variance = npq

Standard Deviation = \sqrt{npq}

Where q would be probability of failure, or "1 - p"

Thus,

n = 100

p = 0.08

q = 1 - 0.08 = 0.92

SO, we have:

Mean = np=100*0.08=8

Variance = npq=100*0.08*0.92 = 7.36

Standard Deviation = \sqrt{npq}=\sqrt{7.36}=2.7129

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