2y - x = 5
x^2 + y^2 - 25 = 0
x = 2y - 5
(2y-5)^2 + y^2 - 25 = 0
(2y-5)(2y-5) + y^2 - 25 = 0
4y^2 - 20y + 25 + y^2 - 25 = 0
5y^2 - 20y = 0
y = 0 , y = 4
x = 2y - 5 , when y = 0
x = - 5
x = 2y - 5 , when y = 4
x = 8 - 5
x = 3
Given:
The graph of a function
.
To find:
The interval where
.
Solution:
From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So,
for
and
.
The function between x=0 and x=3.6 lies below the x-axis. So,
for
.
Now,
For
, the graph of h(x) is above the x-axis. So,
.
For
, the graph of h(x) is below the x-axis. So,
.
For
, the graph of h(x) is below the x-axis. So,
.
Only for the interval
, we get
.
Therefore, the correct option is A.
1. c
2. b
3. a
hope this helps
3 out of 10 quiz because if you divide 3 by 10 it's 0.3 but if you do 4/15 it's 0.26...