Answer: Part A is 2 and 6 Part B is 2
Step-by-step explanation:
Part A: Here is the explanation. So, you started at with the expression 3x^2+8x+4 and when you're are factoring, you have 3x^2+px+pq+4. You can substitute the p and q for 6 and 2. What they did is they replaced 8x with px+qx. To get 8x, p needs to be 6 and q needs to be 2, or the other way around. TIP: The numbers just have to add up to 8 on this one. It doesn't have to be 6 and 2.
Part B: Here is what I got so far... 3x(x+r) is 3x^2+3xr. Also, s(x+r) is sx+sr. The equation becomes, 3x^2+3xr+sx+sr. R can be 2 and s can be 2. Here is my reasoning: The original expression was 3x^2+8x+4. We already have the 3x^2, so now we need to find what the others are by determining what r and s equal. R and s can both be 2 to make four. 2x2 is 4. Let's see if it can make 8. 3xr becomes 6x and sx becomes 2x. 6x+2x is 8x.
All you do is subtract the two numbers
Answer:
-11
Step-by-step explanation:
The generic solution to ...
- a + b = sum
- a - b = difference
Can be found by adding the two equations:
(a+b) + (a-b) = (sum) + (difference)
2a = (sum + difference)
a = (sum + difference)/2
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Our particular solution is ...
a = (-44 +22)/2 = -11
The greater of the two numbers is -11.
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The other number is -33.
Answer:
It's B :)
Step-by-step explanation:
Eliminate the exponent
2^3=8
9^3=729
The simplified answer would be 8/729.
Hope this helps!
