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3 years ago

PLS HELP FAST WILL GIVE BRAINLIEST

Mathematics

1 answer:

amid [387]3 years ago

6 0

Answer:

The values are calculated with the help of table.

Step-by-step explanation:

We are given the following information in the question:

A table is shown showing trees on two different plots of land which are tested for disease.

Tree: 1 2 3 4 5 6 7

Plot: A A B B B A B

Disease: Y N Y Y Y N N

We have to find:

Calculating from the table, we can fill the values as:

Plot A Plot B

Disease Present 1 3

Disease not Present 2 1

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Help rq thank you this is a important test I need help

VikaD [51]

Answer:

Step-by-step explanation:

$\sqrt{15}$ = 3.87

$\sqrt{68}$ = 8.25

Integers between the two:

4, 5, 6, 7, 8

5 numbers in total

6 0

3 years ago

Compute the mean, median, and mode for the following three sets of scores saved.

igor_vitrenko [27]

Answer/Step-by-step explanation:

Score 1:

3, 7, 5, 4, 5, 6, 7, 8, 6, 5

Mean = $\frac{3 + 7 + 5 + 4 + 5 + 6 + 7 + 8 + 6 + 5}{10} = \frac{56}{10} = 5.6$

Median: order the data from least to the greatest.

3, 4, 5, 5, 5, 6, 6, 7, 7, 8

The median is average of the fifth and sixth data value in the data set

Median = (5 + 6)/2 = 11/2 = 5.5

Mode = value with the highest frequency = 5

Score 2:

34, 54, 17, 26, 34, 25, 14, 24, 25, 23

Mean = sum of all values/10

Mean = 276/10 = 27.6

Median: order the data set from min to max.

14, 17, 23, 24, 25, 25, 26, 34, 34, 54

The median is average of the fifth and sixth data value in the data set

Median = (25 + 25)/2 = 50/2 = 25

Mode = 25 and 34 (both have frequencies of 2)

Score 3:

154, 167, 132, 145, 154, 145, 113, 156, 154, 123

Mean = sum of all values/10

Mean = 1443/10 = 144.3

Median: order the data set from min to max.

113, 123, 132, 145, 145, 154, 154, 154, 156, 167

The median is average of the fifth and sixth data value in the data set

Median = (145 + 154)/2 = 299/2 = 149.5

Mode = 154

8 0

4 years ago

Martha has widow's peak and attached earlobes. Martha's dad had a straight hairline and unattached earlobes. If Martha marries a

krok68 [10]

Answer:

the probability of having a widow peak and attached earlobe = 0.6667*0.66667 = 0.4445 = 44.5%

Step-by-step explanation:

Martha = widow's peak + attached earlobes.

Martha's dad = straight hairline + unattached earlobes.

Martha husband =straight hairline+ widow's peak + attached earlobes

what is the probability that Martha child will have a widow's peak + attached earlobes?

since,

Martha + Martha husband =straight hairline+ widow's peak + attached earlobes

the probability of the child having widow peak is 2/3 = 0.6667

the probability of the child having attached earlobes is 2/3 = 0.66667

the probability of having both = 0.6667*0.66667 = 0.4445

6 0

3 years ago

PLEASE HELP!!!!!!!!!!

Sedbober [7]

Answer:

Braden is incorrect because the correct answer is B. He included the top face of the box

Step-by-step explanation:

To find surface area, just add up the areas of all of the sides of the shape. In this case, you would have one side with 144 in^2 (12 * 12) and four sides with 120 in^2 (10 * 12). Add these together and you get 624

4 0

3 years ago

A survey is given to a class, asking about each person's favorite season of

lina2011 [118]

5/10 and 1/2 as they are the same.
Because there are 100 pupils in total.
10 choose summer and 40 choose fall, totalling 50 students out of 100.
=5/10 and 1/2

4 0

3 years ago