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2 years ago

Is anyone really good at math?

Mathematics

2 answers:

Gre4nikov [31]2 years ago

7 0

Answer: 12 cm

Step-by-step explanation:

$\mathtt{Using\ the \ pythagorean \ theorem: \\}$

$a^2+b^2=c^2, \\\ we\ can\ plug\ in\ values\ for\ a,\ b,\ and\ c$

$L=a\ and\ M=b\ and\ N=c$

Therefore,

$L^2+35^2=37^2\\L^2+1225=1369\\L^2=144\\\sqrt{L^2} =\sqrt{144} \\L=\pm12\\Taking\ only\ the\ positive\ answer,\ we\ get:\\\large\boxed{L = 12cm}$

Romashka-Z-Leto [24]2 years ago

5 0

We have: L² + M² = N²

=> L² = N² - M² = 37² - 35² = 144 = 12²

=> L = 12

ANSWER: B.12

OK done. Thank to me :3

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6h^5+0h^4-12h^3+0h^3+0h=0

aliya0001 [1]

<h2>The value of h = 0, ± $\sqrt{2}$ </h2>

Step-by-step explanation:

We have,

$6h^5+0h^4-12h^3+0h^3+0h=0$

To find, the value of h = ?

∴ $6h^5+0h^4-12h^3+0h^3+0h=0$

⇒ $6h^5$ + (0) $h^4$ - 12 $h^3$ + (0) $h^3$ + (0)h = 0

⇒ $6h^5$ + 0 - 12 $h^3$ + 0 + 0 = 0

⇒ $6h^5$ - 12 $h^3$ = 0

Taking 6 $h^3$ as common, we get

$6h^3(h^2-2)$ = 0

⇒6 $h^3$ = 0 or, $h^2$ - 2 = 0

⇒ 6 $h^3$ = 0 ⇒ h = 0

⇒ $h^2$ = 2

⇒ h = ± $\sqrt{2}$

Hence, the value of h = 0, ± $\sqrt{2}$

7 0

4 years ago

Verify the identity. Show your work. 1 + sec^2xsin^2x = sec^2x

allsm [11]

$\bf \textit{Pythagorean Identities}
\\\\
1+tan^2(\theta)=sec^2(\theta)\\\\
-------------------------------\\\\
1+sec^2(x)sin^2(x)=sec^2(x)
\\\\\\
1+\cfrac{1}{cos^2(x)}\cdot sin^2(x)\implies 1+\cfrac{sin^2(x)}{cos^2(x)}\\\\\\ 1+tan^2(x)\implies sec^2(x)$

4 0

4 years ago

Paula, a college student, earned $3,600 one summer. During the following semester, she spent $2,500 for tuition, $650 for rent,

ioda

TO get this answer, we divide the spent money by the earned.
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The answer is 69%

6 0

4 years ago

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vlabodo [156]

Answer:

mmk

Step-by-step explanation:

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3 years ago

Select all ordered pairs that satisfy the function y = 4x + 3

qwelly [4]

Answer:

see explanation

Step-by-step explanation:

To determine which ordered pairs satisfy the equation substitute the x coordinate of the point into the right side and if the value obtained equals the y coordinate of the point then it satisfies the equation

(- 1, - 1)

x = - 1 : y = - 4 + 3 = - 1 ⇒ (- 1, - 1) satisfies the equation

(2, 11)

x = 2 : y = 8 + 3 = 11 ⇒ (2, 11) satisfies the equation

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x = 4 : y = 16 + 3 = 19 ≠ 7 ⇒ (4, 7) does not satisfy the equation

(7, 1)

x = 7 : y = 28 + 3 = 31 ≠ 1 ⇒ (7, 1) does not satisfy the equation

4 0

4 years ago