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3 years ago

What is the 20 digit of 89

Mathematics

1 answer:

Llana [10]3 years ago

7 0

The twentieth digit would be 20. Hope you found this helpful

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The square of a whole number is between 1200 and 1600. The number must be between

gladu [14]

1200 and 1600 iomnlnklk

6 0

3 years ago

A surfer is riding a 7 foot wave. The angle of depression from the surfer to the shoreline is 10 degrees. What is the distance f

denis23 [38]

Step-by-step explanation:

The distance from the surfer to the shoreline will be found as follows:

tan θ= opposite/adjacent

θ=10°

opposite=7ft

adjacent= x ft

substituting the values in our formula and solving for x we get

tan 10=7/x

hence

x=7/tan10

x=39.69897~ 39.7 ft

The surfer is 39.7 ft from the shoreline.

6 0

2 years ago

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What is the image of C for a 90 degree counterclockwise rotation about A?

Mashcka [7]

counter clockwise would be rotating it up to the right.

C is 4 spaces away from A ,

A is on X3 & Y3 so 4 +3 = 7

so it would be x7 & Y3 so (7,3), the first answer

3 0

3 years ago

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In the United States, the mean and standard deviation of adult men's heights are 70 inches (5 feet 10 inches) and 4 inches, resp

Artyom0805 [142]

Answer:

$P(X>72)=P(\frac{X-\mu}{\sigma}>\frac{72-\mu}{\sigma})=P(Z>\frac{72-70}{4})=P(z>0.5)$

And we can find this probability using the complement rule and the normal standard table:

$P(z>0.5)=1-P(z$

And the best solution would be:

c. 0.3085

Step-by-step explanation:

For this case we can convert all the values to inches in order to standardize the solution:

$5ft * \frac{12 in}{1ft}= 60 in$

$6ft * \frac{12 in}{1ft}= 72 in$

Let X the random variable that represent the heights of US mens, and for this case we know the distribution for X is given by:

$X \sim N(70,4)$

Where $\mu=70$ and $\sigma=4$

We are interested on this probability

$P(X>72)$

We can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

Using this formula we got:

$P(X>72)=P(\frac{X-\mu}{\sigma}>\frac{72-\mu}{\sigma})=P(Z>\frac{72-70}{4})=P(z>0.5)$

And we can find this probability using the complement rule and the normal standard table:

$P(z>0.5)=1-P(z$

And the best solution would be:

c. 0.3085

5 0

3 years ago

If a = {6 6 4 7 -4 4 -6 9 -3} and B= {1 5 -8 9 -5 -8 9 -5 2}, find 3a +9B Matrix operations

V125BC [204]

Answer:

$3A+9B=\begin{bmatrix} 27 & 63 & -60 \\\\ 102 & -57 & -60\\\\ 63 & -18 & 9 \end{bmatrix}$

Step-by-step explanation

$A=\begin{bmatrix} 6 & 6 & 4\\\\7 & -4 & 4\\\\ -6 & 9 & -3\end{bmatrix}\: and \: B=\begin{bmatrix}1 & 5 & -8\\\\ 9 & -5 & -8\\\\ 9 & -5 & 2\end{bmatrix}$

$\rightarrow 3A=3\begin{bmatrix} 6 & 6 & 4\\\\7 & -4 & 4\\\\ -6 & 9 & -3\end{bmatrix},\: \: 9B =9\begin{bmatrix}1 & 5 & -8\\\\ 9 & -5 & -8\\\\ 9 & -5 & 2\end{bmatrix}$

$\rightarrow 3A=\begin{bmatrix} 3*6 & 3*6 & 3*4\\\\3*7 & 3(-4) & 3*4\\\\ 3(-6) & 3*9 & 3(-3)\end{bmatrix},\:\: 9B =\begin{bmatrix}9*1 &9* 5 &9( -8)\\\\ 9*9 & 9(-5) & 9(-8)\\\\ 9*9 & 9(-5) & 9*2\end{bmatrix}$

$\rightarrow 3A=\begin{bmatrix} 18 & 18 & 12 \\\\ 21 & -12 & 12\\\\ -18 & 27 & -9\end{bmatrix},\:\: 9B =\begin{bmatrix} 9 & 45 & -72 \\\\ 81 & -45 & -72\\\\ 81 & -45 & 18\end{bmatrix}$

$\rightarrow 3A+9B=\begin{bmatrix}18+9 & 18+45 & 12+(-72) \\\\ 21+81 & -12 +(-45) & 12+(-72)\\\\ -18+81 & 27+(-45) & -9+18 \end{bmatrix}$

$\rightarrow 3A+9B=\begin{bmatrix} 18+9 & 18+45 & 12-72 \\\\ 21+81 & -12 -45 & 12-72\\\\ -18+81 & 27-45 & -9+18 \end{bmatrix}$

$\rightarrow \purple{\bold{3A+9B=\begin{bmatrix} 27 & 63 & -60 \\\\ 102 & -57 & -60\\\\ 63 & -18 & 9 \end{bmatrix}}}$

6 0

2 years ago