Y= - 1/5 x +21 is the slope intercept form
Answer:
Step-by-step explanation:
f(0) = -2
f(1) = 3*(f(1 - 1)) - 2*1
f(1) = 3(-2) - 2
f(1) = - 6 - 2
f(1) = - 8
f(2) = 3*(f(1)) - 2*2
f(2) = 3*(-8) - 4
f(2) = -24 - 4
f(2) = - 28
f(3) = 3*(f(2)) - 2*3
f(3) = 3*-28 - 6
f(3) = -84-6
f(3) = - 90
f(4) = 3*f(3) - 2 * 4
f(4) = 3*-90 - 8
f(4) = -270 - 8
f(4) = -278
The distance all the way around the sidewalk (the circumference) is 300 pi. 45 degrees is 1/8 of 360 degrees, so the two paths cut 1/8 of the circumference. That's 37.5 pi = 117.81 ft. The nearest whole foot is 118 ft.
Answer:
![\dfrac{\$1000+\$20x}{x} \leq \$25](https://tex.z-dn.net/?f=%5Cdfrac%7B%5C%241000%2B%5C%2420x%7D%7Bx%7D%20%5Cleq%20%5C%2425)
Minimum 200 people other than the 2 charity representatives.
Step-by-step explanation:
Given that:
The venue can hold a maximum of 500 people.
Cost of venue = $1000
Per person cost for food = $20
Two charity representatives get to attend the dinner for free.
To find:
The inequality and to determine how many people must come to keep costs at most $25.
Solution:
Let the number of people attending the dinner = ![x](https://tex.z-dn.net/?f=x)
Cost of food for
people = ![\$20x](https://tex.z-dn.net/?f=%5C%2420x)
Total cost = $1000 + ![\$20x](https://tex.z-dn.net/?f=%5C%2420x)
Cost per person = Total cost divided by Number of people attending the dinner.
As per question statement:
![\dfrac{\$1000+\$20x}{x} \leq \$25\\\Rightarrow 1000+20x\leq25x\\\Rightarrow 1000 \leq 5x\\\Rightarrow x\geq 200](https://tex.z-dn.net/?f=%5Cdfrac%7B%5C%241000%2B%5C%2420x%7D%7Bx%7D%20%5Cleq%20%5C%2425%5C%5C%5CRightarrow%201000%2B20x%5Cleq25x%5C%5C%5CRightarrow%201000%20%5Cleq%205x%5C%5C%5CRightarrow%20x%5Cgeq%20200)
Therefore, the answer is:
Minimum 200 people other than the 2 charity representatives should attend the dinner.
Answer:
A
Step-by-step explanation:
The domain of a relation is all the x values in it. Therefore, since the only x values in this relation are -4, -2, 1, and 4 that is the answer.
hope this helps :)