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2 years ago

uhm pueden contestarme esto xfa- es para una amiga y tenemos que tener diferente respuestas si pueden claro :))

Mathematics

1 answer:

agasfer [191]2 years ago

3 0

Answer:

hola

Step-by-step explanation:

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What is the area of the unshaded region

QveST [7]

Need more info please ?

8 0

3 years ago

75 - 3.5x - 4x = 4x + 6

stepladder [879]

Answer:

x = 6

Step-by-step explanation:

Step 1: Write equation

75 - 3.5x - 4x = 4x + 6

Step 2: Solve for <em>x</em>

Combine like terms: 75 - 7.5x = 4x + 6
Add 7.5x on both sides: 75 = 11.5x + 6
Subtract 6 on both sides: 69 = 11.5x
Divide both sides by 11.5: 6 = x
Rewrite x = 6

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

75 - 3.5(6) - 4(6) = 4(6) + 6

75 - 21 - 24 = 24 + 6

54 - 24 = 30

30 = 30

3 0

3 years ago

Read 2 more answers

How many degrees does the hour hand move from 3:00 to 5:30?

hodyreva [135]

now, keeping in mind that a circular clock has 360° total, and there are 12 hours labeled on it evenly, so the angle between each hour label is 360 ÷ 12 = 30.

so, from 3pm to 5pm, it moved by 30° + 30° = 60°.

from 5pm to 5:30, that's only half an hour, so it moved half 30°, or 15°.

60° + 15° = 75°.

4 0

3 years ago

A medical equipment industry manufactures X-ray machines. The unit cost (the cost in dollars to make each X-ray machine) depends

lyudmila [28]

Answer:

$14,362

Step-by-step explanation:

The computation of the minimum unit cost is shown below:

Given that

0.6x^2 - 108x + 19,222

And as we know that the quadratic equation form is

ax^2 + bx + c

where

a = 0.6

b = -108

c = 19,222

Now for determining the minimal cost we applied the following formula which is

$= \frac{-b}{2a} \\\\ = \frac{-(-108)}{2\times 0.6} \\\\ = \frac{108}{1.2}$

= 90

Now put these values to the above equation

$= 0.6\times 90^{2} - 108 \times 90 + 19,222$

= 14,362

8 0

2 years ago

F(x, y, z) = yzexzi + exzj + xyexzk,

Ghella [55]

$\nabla f(x,y,z)=\mathbf F(x,y,z)\iff\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j+\dfrac{\partial f}{\partial z}\,\mathbf k=yze^{xz}\,\mathbf i+e^{xz}\,\mathbf j+xye^{xz}\,\mathbf k$

$\dfrac{\partial f}{\partial x}=yze^{xz}$
$\implies f(x,y,z)=\dfrac{yz}ze^{xz}+g(y,z)=ye^{xz}+g(y,z)$

$\dfrac{\partial f}{\partial y}=e^{xz}=e^{xz}+\dfrac{\partial g}{\partial y}$
$\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

$\dfrac{\partial f}{\partial z}=xye^{xz}=xye^{xz}+\dfrac{\mathrm dh}{\mathrm dz}$
$\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C$

$f(x,y,z)=ye^{xz}+C$

$\mathbf r(t)=(t^2+5)\,\mathbf i+(t^2-1)\,\mathbf j+(t^2-5)\,\mathbf k$
$\implies\mathbf r(0)=5\,\mathbf i-\mathbf j-5\,\mathbf k$
$\implies\mathbf r(5)=30\,\mathbf i+24\,\mathbf j+20\,\mathbf k$

By the gradient theorem, we have for any path $\mathcal C$ originating at the point (5, -1, -5) and terminating at the point (30, 24, 20),

$\displaystyle\int_{\mathcal C}\mathbf F\cdot\mathrm d\mathbf r=f(\mathbf r(5))-f(\mathbf r(0))=f(30,24,20)-f(5,-1,-5)$
$\implies\displaystyle\int_{\mathcal C}\mathbf F\cdot\mathrm d\mathbf r=24e^{600}+e^{-25}$

4 0

3 years ago