Question

A proton is accelerated down a uniform electric field of 450 N/C. Calculate the acceleration of this proton.

Answer 1

Answer:

The acceleration of proton will be $431.137\times 10^8m/sec^2$

Explanation:

We have given electric field E = 450 N/C

Charge on proton $=1.6\times 10^{-19}C$

Force on electron due to electric field is given by $F=qE=1.6\times 10^{-19}\times 450=720\times 10^{-19}N$

Mass of electron $m=1.67\times 10^{-27}kg$

Now according to second law of motion $F=ma$

So $720\times10^{-19}=1.67\times 10^{-27}a$

$a=431.137\times 10^8m/sec^2$

So the acceleration of proton will be $431.137\times 10^8m/sec^2$