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rjkz [21]
3 years ago
7

A 0.50-$kg$ block slides along a small track with elevated ends and a flat central part. The flat part has a length L = 1.00 $m$

. The curved portions of the track are frictionless, but for the flat part the coefficient of kinetic friction is 0.144. The block is released from rest from a height h = 70 $cm$ on the left curved portion of the track. Calculate the maximum height reached by the block on the right curved portion of the track.

Physics
1 answer:
Annette [7]3 years ago
6 0

Answer:

y=55.6 cm

Explanation:

Given that

m=0.5 kg

L= 1 m

h= 70 cm = 0.7 m

coefficient of kinetic friction( μ ) = 0.144

Lets take maximum of height achieved by block on the right side

The friction force on the flat part

fr= μ  m g

Initial velocity at the top left is zero and the final speed of the bock at right top will be zero .

we know that work done by all force = Change in kinetic energy

Here initial and final speed is zero so the change in kinetic energy is zero.

m g h - fr . L - m g y=0

fr= μ  m g

m g h - μ  m g .L  - m g y=0

h - μ.L - y = 0

By putting the values

0.7 - 0.144 x 1 - y = 0

y=0.556 m

y=55.6 cm  

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3 years ago
A type of energy embodied in oscillating electric and magnetic fields is called
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Explanation:

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4 0
2 years ago
What quantity of heat is needed to convert 1 kg of ice at -13 degrees C to steam at 100 degrees C?
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Answer:

Heat energy needed = 3036.17 kJ

Explanation:

We have

     heat of fusion of water = 334 J/g

     heat of vaporization of water = 2257 J/g

     specific heat of ice = 2.09 J/g·°C

     specific heat of water = 4.18 J/g·°C

     specific heat of steam = 2.09 J/g·°C

Here wee need to convert 1 kg ice from -13°C to vapor at 100°C

First the ice changes to -13°C from 0°C , then it changes to water, then its temperature increases from 0°C to 100°C, then it changes to steam.

Mass of water = 1000 g

Heat energy required to change ice temperature from -13°C to 0°C

          H₁ = mcΔT = 1000 x 2.09 x 13 = 27.17 kJ

Heat energy required to change ice from 0°C to water at 0°C

          H₂ = mL = 1000 x 334 = 334 kJ

Heat energy required to change water temperature from 0°C to 100°C  

          H₃ = mcΔT = 1000 x 4.18 x 100 = 418 kJ    

Heat energy required to change water from 100°C to steam at 100°C  

          H₄ = mL = 1000 x 2257 = 2257 kJ    

Total heat energy required

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5 0
3 years ago
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Answer:

115 kPa

Explanation:

Use Bernoulli equation:

P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂

Assuming no elevation change, h₁ = h₂.

P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²

Plugging in values:

(582,000 Pa) + ½ (1000 kg/m³) (1.28 m/s)² = P + ½ (1000 kg/m³) (30.6 m/s)²

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3 0
3 years ago
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Answer:

P = 1333.33 N

Explanation:

The pressure exerted by the boy on the floor can be calculated by the following equation:

P = \frac{F}{A}

where,

P = Pressure exerted by the boy = ?

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A = Area of application of force = 2(Area of one show) = 2(6 cm x 25 cm)

A = 2(0.06 m x 0.25 m) = 0.03 m²

Therefore,

P = \frac{40\ N}{0.03\ m^2}\\\\

<u>P = 1333.33 N</u>

4 0
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