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erica [24]
2 years ago
10

Glenn shoots an arrow at a 30.0 degree angle. It has a velocity of 65.0 m/s How far will the arrow travel?

Physics
1 answer:
Burka [1]2 years ago
3 0
I just shot my shot at this little 52 ms far
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URGENT! PLEASE ANSWER!!
Marrrta [24]

Answer:

C

Explanation:

The answer is obvious from the given figure

7 0
3 years ago
What’s contact force ?
kodGreya [7K]

Explanation:

Contact force is any force that requires contact.  An object that exerts a force on another object by touching it is exerting a contact force.  Examples of contact force are friction and normal force.

Examples of a non-contact force are gravity and magnetism.

5 0
3 years ago
Read 2 more answers
A tall tube is evacuated and its stopcock is closed. The open end of the tube is immersed in a container of water (density 10^3
LuckyWell [14K]

Answer:

10.19 m

Explanation:

Water will rise to equalize the pressure inside and outside the tube.

The equation of pressure is given by

p=\rho gh

Where,

p = Pressure of air = 10⁵ N/m²

ρ = Density of water = 10³ kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Height the water will rise

h=\frac{p}{gh}\\\Rightarrow h=\frac{10^5}{9.81\times 10^3}\\\Rightarrow h=10.19\ m

∴ The water will rise by 10.19 m.

7 0
3 years ago
A wave travels at a constant speed. How does the frequency change if the wavelength increases by a factor of 2?
NARA [144]

Answer : The frequency decreases by a factor of 2.

Explanation :

Given that the wave travels at a constant speed. The speed of the wave is given as :

v=\nu\times \lambda

Where

υ is the frequency of the wave

and λ is the wavelength of the wave.

In this case, the speed is constant. So, the relation between the frequency and the wavelength is inverse.

\nu\propto \dfrac{1}{\lambda}

If the wavelength increases by a factor of 2, its frequency will decrease by a factor of 2.

Hence, the correct option is (A) " The frequency decreases by a factor of 2 ".

3 0
3 years ago
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a body dropped from a height reaches a velocity of 13m/s just before touching the ground. What is the initial height of the ball
SashulF [63]

Hi there!

We can use the following (derived) equation to solve for the final velocity given height:

vf = √2gh

We can rearrange to solve for height:

vf² = 2gh

vf²/2g = h

Plug in the given values (g = 9.81 m/s²)

(13)²/2(9.81) = 8.614 m

We can calculate time using the equation:

vf = vi + at, where:

vi = initial velocity (since dropped from rest, = 0 m/s)

a = acceleration (in this instance, due to gravity)

Plug in values:

13 = at

13/a = t

13/9.81 = 1.325 sec

5 0
2 years ago
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