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Georgia [21]
3 years ago
5

If a water wave completes one cycle in 2 seconds, what is the period of the wave?

Physics
1 answer:
Luba_88 [7]3 years ago
4 0

Answer:

period = 2 seconds.

Explanation:

Recall that period is the time needed to complete one cycle. Therefore the period of the given wave is 2 seconds.

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Which of the following best describes the suns size compared with other stars?
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1) D: enormous
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A 1.2 g pebble is stuck in a tread of a 0.76 m diameter automobile tire, held in place by static friction that can be at most 3.
Maksim231197 [3]

Answer:

v=33.764m/s

Explanation:

Given data

Mass m=1.2 g=0.0012 kg

diameter d=0.76 m

Friction Force F=3.6 N

To find

Velocity v

Solution

From the Centripetal force we know that

F_{c}=\frac{mv^{2} }{r}

Where m is mass

v is velocity

r is radius

Substitute the given values to find velocity v

So

F_{c}=\frac{mv^{2} }{r}\\v^{2}=\frac{F_{c}(r)}{m}\\ v=\sqrt{\frac{F_{c}(r)}{m}}\\ v=\sqrt{\frac{F_{c}(diameter/2)}{m}}\\v=\sqrt{\frac{(3.6N)(0.76/2)m}{(0.0012kg)}}\\v=33.764m/s

4 0
3 years ago
Consider the reaction, X + 2Y → XY2 If X and Y are completely consumed in the reaction and we start with 10.0 mol of Y, then how
Harrizon [31]

Answer:

In the reaction you would have 15.0 mols of Y and X.

Explanation:

The stoichiometric coefficents for X and Y are 1 and 2 respectively, if you start the reaction with 10.0 moles of Y you would need 5.0 moles of X in order to achieve a complete reaction so you will have 15.0 total moles in the reaction, assuming no mass loss and no nuclear reactions.

3 0
3 years ago
Bacteria which do not live in extreme conditions are found in which kingdom:
mel-nik [20]
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8 0
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An instructor wishes to determine the wavelength of the light in a laser beam. To do so, she directs the beam toward a partition
Rus_ich [418]

Answer:

λ = 623.2 nm

Explanation:

We are given;

separation distance; d = 0.195 mm = 0.195 × 10^(-3) m

interference pattern distance; D = 4.85 m

Width of two adjacent bright interference; w = 1.55 cm = 1.55 × 10^(-2) m

Formula for fringe width is given as;

w = λD/d

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Thus;

λ = dw/D

λ = (0.195 × 10^(-3) × 1.55 × 10^(-2))/4.85

λ = 0.0000006232 m

Converting to nm gives;

λ = 623.2 nm

6 0
3 years ago
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