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Georgia [21]
3 years ago
5

If a water wave completes one cycle in 2 seconds, what is the period of the wave?

Physics
1 answer:
Luba_88 [7]3 years ago
4 0

Answer:

period = 2 seconds.

Explanation:

Recall that period is the time needed to complete one cycle. Therefore the period of the given wave is 2 seconds.

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Acceleration is a measure of the change in the velocity of an object per unit time true or false
Ksju [112]

This is true. Hope I helped!

3 0
3 years ago
Read 2 more answers
A football was kicked so that it traveled 65 yards in 3.0 total seconds. What was the speed
Olin [163]

Answer:

vx = 65 yd/3 sec  = 21.7 yd/sec  since horizontal speed is constant

vy = g t = (32 / 3) yd/sec^2 * 1.5 sec = 16 yd/sec   where 32/3 is the acceleration due to gravity in yds / sec^2  and 1.5 is the time to travel each way in the vertical direction

V = (vx^2 + vy^2)^1/2 = (21.7^2 + 16^2)^1/2 = 27 yd/sec

tan theta = vy/vx = 16 / 21.7 = .737    theta = 36.4 deg

You can check using the range formula:

R = v^2 sin (2 theta) / g = 27^2 * .955 / (32 / 3) = 65.3 yds  

The difference from 65 yds may be rounding error.

4 0
4 years ago
An electron accelerated from rest through a voltage of 780 v enters a region of constant magnetic field. part a part complete if
maxonik [38]
The electron is accelerated through a potential difference of \Delta V=780 V, so the kinetic energy gained by the electron is equal to its variation of electrical potential energy:
\frac{1}{2}mv^2 =  e \Delta V
where
m is the electron mass
v is the final speed of the electron
e is the electron charge
\Delta V is the potential difference

Re-arranging this equation, we can find the speed of the electron before entering the magnetic field:
v= \sqrt{ \frac{2 e \Delta V}{m} } = \sqrt{ \frac{2(1.6 \cdot 10^{-19}C)(780 V)}{9.1 \cdot 10^{-31} kg} }=1.66 \cdot 10^7 m/s


Now the electron enters the magnetic field. The Lorentz force provides the centripetal force that keeps the electron in circular orbit:
evB=m \frac{v^2}{r}
where B is the intensity of the magnetic field and r is the orbital radius. Since the radius is r=25 cm=0.25 m, we can re-arrange this equation to find B:
B= \frac{mv}{er}= \frac{(9.1 \cdot 10^{-31}kg)(1.66 \cdot 10^7 m/s)}{(1.6 \cdot 10^{-19}C)(0.25 m)} =3.8 \cdot 10^{-4} T
3 0
4 years ago
Vector A points north and vector B points east. If c = B - A , then vector C points where?
Sergio [31]

Answer:

South of East

Explanation:

7 0
3 years ago
1. A jet lands on an aircraft carrier at a speed of 140 mi/h [ 1.00 mile = 1.61 km]
Iteru [2.4K]
Answer:

Acceleration, a = -31.29 m/s²

Explanation:

It is given that, Initial speed of the aircraft, u = 140 mi/h =

62.58 m/s

Finally, it stops, v = 0

Time taken, t = 2 s

Let a is the acceleration of the aircraft. We know that the rate of change of velocity is called acceleration of the object. It is given by :

a = t

0-62.58 2 a =

a = -31.29 m/s²

So, the acceleration of the aircraft is 31.29 m/s²

and the car is decelerating. Hence, this is the required solution.
(i found this answer becuase i could do the math)

5 0
3 years ago
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