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3 years ago

Based on the data set shown, which of the following is a true statement?

2 answers:

6 0

Start by identifying your mean.

Add all of your values together and then divide by the total number of values.
11/11 is 1

So your mean is 1.

The mode is the most common number in the data set, which is also 1. The number 1 is most frequent in the set.

So this makes A the correct answer.

patriot [66]3 years ago

3 0

The mean, median, and mode are equal to 1. So among the choices, the first one is correct - mean = mode

Mean - an average of the given set of number; to find this, add the numbers and divide it by 11 (the number of given data)
= (-1 + -1 + 0 + 1 + 1 + 1 + 1 + 2 + 2 + 2 + 3) / 11
= 1

Median - the middle or center of the given set; to find this, arrange the numbers in numerical order, then get the center or middle number as the median
= -1, -1, 0, 1, 1, 1, 1, 2, 2, 2, 3
= [-1, -1, 0, 1, 1,] 1, [1, 2, 2, 2, 3]

Mode - is the value that occurs most of the time in the given set; so obviously number 1 occurred four times so 1 is our mode

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Answer:

$p_v =P(t_{74}$

If we compare the p value and a significance level for example $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

Step-by-step explanation:

Data given and notation

$\bar X=18.81$ represent the average lateral recumbency for the sample

$s=8.4$ represent the sample standard deviation

$n=75$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to apply a left tailed test.

What are H0 and Ha for this study?

Null hypothesis: $\mu \geq 20$

Alternative hypothesis : $\mu < 20$

Compute the test statistic

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{18.81-20}{\frac{8.4}{\sqrt{75}}}=-1.227$

The degrees of freedom are given by:

$df=n-1=75-1=74$

Give the appropriate conclusion for the test

Since is a one side left tailed test the p value would be:

$p_v =P(t_{74}$

Conclusion

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Step-by-step explanation:

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