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aliina [53]
3 years ago
6

Explain how an enlargement of reduction in the dimensions of a building would cause a change in the scale factor.

Mathematics
1 answer:
Delicious77 [7]3 years ago
6 0

Answer:

The scale factor represents a proportional relationship between the scale drawing and the building’s dimensions. If the dimensions change, then the scale factor must also change to preserve the relationship.

Step-by-step explanation:

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3) This decimal is colored to show<br> 1
MAVERICK [17]
I believe it’s the first one. i’m very sorry if it’s wrong
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3 years ago
Which of the following expressions is equivalent to -9?
FromTheMoon [43]

B because there is only one negative and -63 divided by 7 equals -9. If it were -7 divided by 63 that would give you an answer in decimal form.

6 0
3 years ago
Which of the statements about the following quadratic equation is true?
Sedaia [141]
After manipulating above equation we get, 2x^2 - 7x - 8= 0. Discriminant= b^2 - 4ac = (-7)^2 - 4(2)(-8) = 113>0. So there are 2 real roots :)
3 0
3 years ago
Read 2 more answers
Solve (16×^3-3×^2+43×-5)÷(×^2-2)
Oksana_A [137]

Answer:

3872/(x^2 - 2)

Step-by-step explanation:

Simplify the following:

(16^3 - 3^2 - 5×43)/(x^2 - 2)

3^2 = 9:

(16^3 - 9 - 5×43)/(x^2 - 2)

16^3 = 16×16^2:

(16×16^2 - 9 - 5×43)/(x^2 - 2)

| 1 | 6

× | 1 | 6

| 9 | 6

1 | 6 | 0

2 | 5 | 6:

(16×256 - 9 - 5×43)/(x^2 - 2)

16×256 = 4096:

(4096 - 9 - 5×43)/(x^2 - 2)

43 (-5) = -215:

(4096 - 9 + -215)/(x^2 - 2)

4096 - 9 - 215 = 3872:

Answer: 3872/(x^2 - 2)

7 0
3 years ago
Please help ASAP!
Kruka [31]

First, recall that

\sin(-\theta)=-\sin\theta

So if \sin(-\theta)=\dfrac15, then \sin\theta=-\dfrac15.

Second,

\tan\theta=\dfrac{\sin\theta}{\cos\theta}

We know that \tan\theta>0 and \sin\theta, which means we should also have \cos\theta.

Third,

\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\pm\sqrt{1-\sin^2\theta}

but as we've already shown, we need to have \cos\theta, so we pick the negative root.

Finally,

\tan\theta=\dfrac{\sin\theta}{\cos\theta}\iff\dfrac6{\sqrt{12}}=\dfrac{-\frac15}{\cos\theta}\implies\cos\theta=-\dfrac1{5\sqrt3}

Unfortunately, none of the given answers match, so perhaps I've misunderstood one of the given conditions... In any case, this answer should tell you everything you need to know to find the right solution from the given options.

6 0
3 years ago
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