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aliina [53]
3 years ago
6

Explain how an enlargement of reduction in the dimensions of a building would cause a change in the scale factor.

Mathematics
1 answer:
Delicious77 [7]3 years ago
6 0

Answer:

The scale factor represents a proportional relationship between the scale drawing and the building’s dimensions. If the dimensions change, then the scale factor must also change to preserve the relationship.

Step-by-step explanation:

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Can you please help me....Thank you!
PIT_PIT [208]

Answer:

#1

mean=7

median=8

range=9

mode=3

#2

mean=15

mode=17

range=14

median=14

#3

mean=11

mode=none

range=10

median=4.5

#4

mean=6

mode=4

range=13

median=4

Step-by-step explanation:

there you go, I think that's right but it's been awhile since I've had to do mode mean median and range

4 0
2 years ago
The length of the base of a triangle is twice its height. if the area of the triangle is 196 square​ kilometers, find the height
NISA [10]
Area = 1/2 x base x height

Let the height be x.
Height = x
Base = 2x

Area of triangle = 1/2 x base x  heght

Plug base and height into the variables:
(1/2)(2x)(x) = 196

Combine like terms:
x² = 196

Square root both sides:
x = 14

Find Base and height:
Base = x = 14 km
Height = 2x = 2(14) = 28 km

Answer: Height = 28km
4 0
3 years ago
Read 2 more answers
What's the explicit formula to find the account balance ??
igor_vitrenko [27]
The one and only answer is b
5 0
3 years ago
Solve the inequality
riadik2000 [5.3K]
The answer is D. V< 1 23/25.
3 0
3 years ago
Given the sample 4, −2, −6, 19, 6, add one more sample value that will neither change the mean nor the variance. Round to two de
DedPeter [7]

Answer:

Cannot create sample

Step-by-step explanation:

We are given the following in the question:

4, -2, -6, 19, 6

Formula:

\text{Variance} = \displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{21}{5} = 4.2

Sum of squares of differences = 0.04 + 38.44 + 104.04 + 219.04 + 3.24 = 364.8

s^2 = \dfrac{364.8}{4}} = 91.2

If we add an observation equal to the mean of given sample, then the mean and of new sample will not change.

New sample:

4, -2, -6, 19, 6, 4.2

Mean =\displaystyle\frac{25.2}{6} = 4.2

Sum of squares of differences = 0.04 + 38.44 + 104.04 + 219.04 + 3.24 + 0 = 364.8

s^2 = \dfrac{364.8}{5}} = 72.96

Thus, the variance of new sample changes.

Thus, it is not possible to create a sample.

5 0
3 years ago
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