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4 years ago

Help please I need help

Mathematics

1 answer:

kirza4 [7]4 years ago

7 0

Move the constant to the right by adding it’s opposite to both sides
x+2-2= 7 squared - 2
Next remove the opposites
x= 7 squared -2 is your answer

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A line with a slope of 10 passes through the points ( -5, - 9) and ( - 4,a). What is the value of a?

Setler79 [48]

The slope is 10
(-5,-9)
(-4,-a)
a=-19
Because the slope is 10, that means when the input increases, the output will increases 10.

4 0

4 years ago

On a farm there was a cow. And on the farm there were 2 sheep. There were also 3 chickens. What is the total mass of the 1 cow,

RoseWind [281]

The total mass of the living things on the farm is 588 kg.

<h2><u>Mass calculation</u></h2>

Since on a farm there was a cow, 2 sheep and 3 chickens, to determine what is the total mass of the 1 cow, the 2 sheep, the 3 chickens, and the 1 farmer on the farm, the following calculation must be performed :

(6.2 x 10) + (4 x 10 x 10) + (2 x 6 x 10) + (3 x 2 x 1) = X
62 + 400 + 120 + 6 = X
588 = X

Therefore, the total mass of the living things on the farm is 588 kg.

Learn more about mass calculation in brainly.com/question/14695611

8 0

2 years ago

How do I 'Factor the expression 12p+30.' ?

s2008m [1.1K]

Answer:

Grouping and then use the common factor. Therefor the answer is 6(2p+5)

Step-by-step explanation:

I hope this helps.

5 0

3 years ago

Read 2 more answers

The equation of a circle is (x + 6)^2 + (y - 4)^2 = 16. The point (-6, 8) is on the circle.

pantera1 [17]

Answer:

y = 8 is the equation of tangent.

Step-by-step explanation:

The equation of the tangent to the circle at (-6,8) is of the form:

y = mx + c

where m is the slope of the tangent and c is the y-intercept.

The point (-6,8) lies on the circle and the tangent line as well.

Hence (-6,8) satisfies the line equation:

8 = m(-6) + c ⇒ c-6m = 8 -------------1

We know that slope of two perpendicular lines are related as:

$m_{1}\times m_{2}=-1$

At any point on the circle, the normal line at a point is always perpendicular to the tangent line at that point.

Hence :

$m_{normal} \times m_{tangent}=-1$

We can find the slope of the normal at point (-6,8) as it passes through the centre of the circle (-6,4) by using the two-points formula for slope.

$m=\frac{y_2-y_1}{x_2-x_1}$

$=\frac{8-4}{-6+6}$

= ∞

Slope of the normal is infinity and hence slope of tangent is -1/∞ = 0

Hence m=0

Putting m=0 in equation 1 we get:

c = 8

The equation of tangent line at (-6,8) is:

y = 8

6 0

3 years ago

Express 3 log x^2 + 7 log x as a single log

miss Akunina [59]

Answer:

log x^13.

Step-by-step explanation:

Using the laws of logarithms

a log b = log b^a and log a + log b = log ab:

3 log x^2 + 7 log x

= log (x^2)^3 + log x^7

= log x^6 + log x^7

= log (x^6*x^7)

= log x^13.

8 0

3 years ago