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4 years ago

Please help i don’t understand

Mathematics

1 answer:

vladimir2022 [97]4 years ago

3 0

First, find the wage colum. 614.89 is between the 600 and 620. Then go down the row of 2 exemptions and you'll get 20.81
Next, 359.50 is between the 340 and 360 in the wage colum. Go across the chart with your left figure while your right figure goes down the row of 0 exceptions to find 18.91
Finally, 708.75 is between 700 and 720 and meet it I'm the row for 1 exemption and you'll find 28.46

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A trapezoid has an altitude of 12 cm. Its parallel sides measure 10 and 8 cm, respectively. What is its area? 216 cm² 108 cm² 96

iren2701 [21]

Answer:

108 cm^2

Step-by-step explanation:

A trapezoid has an altitude of 12 cm. Its parallel sides measure 10 and 8 cm, respectively.

The base of trapezoid are 10 and 8 cm

Height of a trapezoid = 12cm

Area of a trapezoid formula = $\frac{a+b}{2} * height$

= $\frac{10+8}{2} * 12$

=108cm^2

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3 years ago

Inspecting Restaurants How many different ways can a city health department inspector visit restaurants in a city with restauran

tankabanditka [31]

Answer:

252 ways

Step-by-step explanation:

The missing details are:

$n = 10$ --- total restaurants

$r = 5$ --- restaurants to visit

Required

The number of ways to perform the visitation

The question is an illustration of combination;

So, we have:

$^nC_r = \frac{n!}{(n - r)!r!}$

This gives:

$^{10}C_5 = \frac{10!}{(10 - 5)!*5!}$

$^{10}C_5 = \frac{10!}{5!*5!}$

Expand

$^{10}C_5 = \frac{10*9*8*7*6*5!}{5!*5*4*3*2*1}$

Cancel out 5!

$^{10}C_5 = \frac{10*9*8*7*6}{5*4*3*2*1}$

$^{10}C_5 = \frac{30240}{120}$

$^{10}C_5 = 252$

4 0

3 years ago

A family has four children. If the genders of these children are listed in the order they are born, there are sixteen possible o

Agata [3.3K]

Answer:

$\begin{array}{cccccc}X&0&1&2&3&4\\Pr&\dfrac{1}{16}&\dfrac{1}{4}&\dfrac{3}{8}&\dfrac{1}{4}&\dfrac{1}{16}\end{array}$

Step-by-step explanation:

A family has four children. If the genders of these children are listed in the order they are born, there are sixteen possible outcomes: BBBB, BBBG, BBGB, BGBB, GBBB, BGBG, GBGB, BGGB, GBBG, BBGG, GGBB, BGGG, GBGG, GGBG, GGGB, and GGGG.

Let X represent the number of children that are girls. Then

1. When X=0, there is one possible outcome BBBB. So

$Pr(X=0)=\dfrac{1}{16}$