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Fed [463]
3 years ago
14

Pls help it has something to do with probability and statistics

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
3 0

Answer:

96

Step-by-step explanation:

8*12=96

whenever you have to find the total # of something just multiply all the integers

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I wished I’d bought the game last week for $199.00. I missed the sale, and now it’s an additional 25%. What will it cost me now
kumpel [21]
199•25%=49.75
49.75+199=248.75
248.75•7.5%=18.65625
18.65625+248.75=267.40625
therefore the answer is $248.41
4 0
3 years ago
What is the domain and limit(s) of f(x)=1/x+3?
SVEN [57.7K]
Find the domain by finding where the function is defined. The range is the set of values that’s correspond with the domain
7 0
2 years ago
I need help on this problem please help me.
a_sh-v [17]

Answer:

150 mL

Step-by-step explanation:

Let x represent the quantity of 75% solution needed. The total amount of alcohol in the 60% mixture will be ...

75%·x + 10%·45 = 60%·(x+45) . . . . . there will be x+45 mL of solution in the end

0.15x = 22.5 . . . . . . . . . . . . . . . . . . . . simplify, subtract .60x+4.5

22.5/0.15 = x = 150 . . . . . . . . . . . . . . mL of 75% solution needed

You will need 150 mL of the 75% solution.

3 0
3 years ago
X + 2y = 7<br> 3x - 2y = -3
VladimirAG [237]
Use Subtraction

1. Subtract
x+2y=7
3x-2y=-3
-------------
4x+0y=4 SIMPLIFY 4x=4

2. DIVIDE

4x=4
x=1

Substitute that into either of the original equations to get x=1, y=3





4 0
3 years ago
Suppose that you can only use the set of small letters characters (a-z) and odd numbers (1, 3, 5, 7, 9) to set a password. What
Flauer [41]

Answer:

31^8

Step-by-step explanation:

To create a password, you need to select 8 characters (not necessarily different) from the set {1,3,5,7,9,a,b,c,...,z}. Now, this set has 31 elements: the 26 lowercase letters from the alphabet and the 5 odd numbers (1,3,5,7,9).

Now, there are 31 ways to choose the first character, it can be any element from our set. The second character can also be chosen in 31 ways, because there are not restrictions (repetitions, specific characters, etc). Similarly, the third, fourth, fifth, sixth, seventh and eighth characters have 31 possibilities each one.

The number of passwords is the number of ways of selecting the 8 characters, then by the multiplication principle the number of passwords is 31×31×31×31×31×31×31×31=31^8.

6 0
3 years ago
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