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3 years ago

Solve the system of linear equations. separate the x- and y- values with a coma. -8x=72-16y

1 answer:

8 0

Let's use the "elimination by addition/subtraction" method to solve this system for x and y.

 -8x=72-16y
4x=-92+16y <= Mult. all 3 terms by 2: 8x = - 184 + 32y

Now combine the following, column by column:

 -8x= 72-16y
8x = - 184 + 32y
-----------------------
0 = -112 + 16y. Solving for y, 16y = 112, and y = 7.

Now subst. 7 for y in either of the original equations and calculate x:

4x=-92+16(7) => 4x = -92 + 112 = 20. Then x = 5.

Solution is 5, -7 (or, better written) (5, - 7).

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In rectangle ABCD, if the coordinates of A are (0, 0) and of C are (r, s), find the coordinates of B and D.

goldenfox [79]

Answer:

Answers are (r,0) and (0,s)

Step-by-step explanation:

Given that in a rectangle ABCD, one vertex is the origin (0,0) A

The opposite vertex C is having coordinates as (r,s)

Since a rectangle has angle 90 we have x axis as one side and y axis as other side.

Length = r and width =s (since coordinates of C are (r,s))

Hence other coordinate B on x axis would be = (r,0)

and D on y axis = (0,s)

Answers are (r,0) and (0,s)

3 0

3 years ago

Read 2 more answers

10% of what number is 300?

sergij07 [2.7K]

10% of what number is 300?

This means that the number is greater than 300 and in fact 10 times greater. You can create and equation. Let x be the number.

0.1x=300

x=3000

answer:3000

8 0

3 years ago

The table shows the distance Shannon ran over a week.

Sedbober [7]

Answer:

Shannon run 1.5 km more on Friday than on Saturday.

Step-by-step explanation:

From the given table

Distance run on Friday = 4/2 = 2 km

Distance run on Saturday = 1/2 = 0.5 km

In order to run how many more kilometers Shannon run on Friday than on Saturday, we need to subtract the distance run on Saturday from the distance run on Friday.

i.e.

Friday run - Saturday run = 2 - 0.5

= 1.5 km

Thus, Shannon run 1.5 km more on Friday than on Saturday.

8 0

3 years ago

PLEASE HELP ME I'M CONFUSED

just olya [345]

I have no idea I’m doing the same thing rn but good luck bro bro

3 0

2 years ago

Read 2 more answers

For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12

notsponge [240]

The binomial distribution is given by,
P(X=x) = $(^{n}C_{x})p^{x} q^{n-x}$
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability of obtaining a score less than or equal to 12.
∴ P(X≤12) = $(^{100}C_{x})(0.2)^{x} (0.8)^{100-x}$
where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12
∴ P(X≤12) = $(^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1}$ + $(^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3}$ + $(^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5}$ + $(^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7}$ + $(^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9}$ + $(^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11}$ + $(^{100}C_{12})(0.2)^{12} (0.8)^{100-12}$

Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability.

7 0

3 years ago