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Vera_Pavlovna [14]
3 years ago
10

Find the zeros of the quadratic function. Solve by factoring. x^2+14x=-45

Mathematics
1 answer:
Reptile [31]3 years ago
3 0

So, x^2 + 14 x + 49 - 4 = 0;

Then, we use the formula ( a + b )^2 = a^2 + 2ab + b^2;

We have ( x + 7 )^2 - 2^2 = 0;

Then, ( x + 7 )^2 - 2^2 = 0;

We use the formula a^2 - b^2 = ( a - b)( a + b );

We obtain ( x + 5 )( x + 9) = 0;

Then, x + 5 = 0;

x = -5;

x + 9 = 0;

x = - 9;

-5 and - 9 are the zeros of the quadratic function.

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a triangle has one leg of 32 inches and one leg of 18 inches. For the triangle to be a right triangle, which best represents the
scZoUnD [109]
You take the square roots √18²+32² = 36.7 
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A certain city in Washington has a population of 46,400 people.
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Step-by-step explanation:

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valentina_108 [34]

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6 0
3 years ago
Help please! <br> find the area of the isoceles triangle
DiKsa [7]

Answer:

This is a long answer. I got 82.5

Step-by-step explanation:

Area of isoceles triangle is

\frac{1}{2} (b)(h)

where b is the base and h is height.

Let draw a altuide going through Point D that split side FE into 2 equal lines. Let call that point that is equidistant from FE, H.

Since it is a altitude,it forms a right angle. So angle H=90.

Angle H is equidistant from F and E so

FH=11

EH=11.

The height is still unknown.

We can use pythagorean theorem to find side h but we need to know the slanted side or side DF to use the theorem.

Using triangle DFH, we know that angle H is 90 and angle F is 34. So using triangle interior rule,Angle D equal 56.

  • We know side FH=11
  • We know Angle D equal 56
  • We are trying to find side DF
  • We know angle H equal 90

We can use law of sines to find side DF

\frac{fh}{ \sin(d) }  =  \frac{df}{ \sin(h) }

Plug in the numbers

\frac{11}{ \sin(56) } =  \frac{df}{ \sin(90) }

sin of 90 =1 so

\frac{11}{ \sin(56) }  = df

Side df is about 13.3 inches.

Since we know our slanted side is 13.3 we can set up our pythagorean theorem equation,

(fh) {}^{2}  + (dh) {}^{2}  = df {}^{2}

(11) {}^{2}  +( dh) {}^{2}  = (13.3) {}^{2}

121 + dh {}^{2}  = 176.89

(dh) {}^{2}  = 55.89

\sqrt{55.89}  = 7.5

is approximately 7.5 so dh=7.5 approximately.

Now using base times height times 1/2 multiply them out

\frac{1}{2} (22)(7.5)

82.5

8 0
3 years ago
Solve the inequality 5 ⎯ 1/2x &gt; 30
aev [14]

Answer:

X<-50

Step-by-step explanation:

multiply both sides by 2,  then you move the constant to the right 10-X>60, then subtract the numbers -X>60-10  and for last you just change the sings  so that gives u your answer  x<-50    

8 0
3 years ago
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