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2 years ago

Simplify the expression 6x/2(3x^2+2)+1/4(×+2)

Mathematics

1 answer:

pentagon [3]2 years ago

7 0

Tell me if the answer is correct and if can give me brainliest hehehe

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When Derek planted a tree it was 36 inches tall. The tree grew 1 1/4 inches per year. The tree is now 44 3/4 inches tall. How ma

Tcecarenko [31]

148

Step-by-step explanation:

44 3/4 : 11/4 =?

if you do this you will find the solution =>years

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Let k ( x ) = 2 x + 3 and m ( x ) = 3 x 2 + 7 x − 10 . Find the indicated value. M ( k ( − 4 ) ) =

murzikaleks [220]

Answer: $30$

Step-by-step explanation:

Given

$k(x)=2x+3$

$M(x)=3x^2+7x-10$

$M\left(k(x)\right)$ is given by replacing the $x$ by $k(x)$ from the $M(x)$

$\Rightarrow M\left(k(x)\right)=3(2x+3)^2+7(2x+3)-10\\\Rightarrow M\left(k(x)\right)=3(4x^2+9+12x)+14x+21-10\\\Rightarrow M\left(k(x)\right)=12x^2+50x+38$

Now, $M\left(k(-4)\right)$ is

$\Rightarrow M\left(k(-4)\right)=12(-4)^2+50(-4)+38\\\Rightarrow M\left(k(-4)\right)=192-200+38\\\Rightarrow M\left(k(-4)\right)=30$

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2 years ago

Use the function f(x) = 2x3 - 3x2 + 7 to complete the exercises.

zavuch27 [327]

Answer:

what are the excersises

Step-by-step explanation:

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2 years ago

single die is rolled twice. Find the probability of rolling an oddodd number the first time and a number greater than 33 the sec

givi [52]

Answer:

$\frac{1}{4}$

Step-by-step explanation:

A single die is rolled twice, we have to find the probability of rolling an odd number in first throw and a number greater than 3 in the second throw.

a) Rolling an Odd number in first throw

A die has total 6 possible outcomes, out of which 3 are odd numbers i.e. 1,3 and 5

So, total number of possible outcomes = 6

Total Favorable outcomes (Odd numbers) = 3

Probability is defined as the ratio of favorable outcomes to total number of outcomes. So,

The probability of rolling an odd number would be = $\frac{3}{6} = \frac{1}{2}$

b) Rolling a number greater than 3 in second throw

Here again total possible outcomes = 6

Favorable outcomes (Numbers greater than 3 are 4, 5 and 6) = 3

So,

The probability of rolling a number greater than 3 = $\frac{3}{6} = \frac{1}{2}$

These two events(rolls) are independent of each other, so the overall probability of both events occurring would be the product of individual probabilities.

So,

Probability of rolling an odd number the first time and a number greater than 3 the second time = $\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$

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2 years ago

My cousin needs help with this

9966 [12]

Answer:

Step-by-step explanation:

if she practiced for 4 hours, we can go to the 4-hour mark and go upward until we see the dot. the dot lands on 3 hits every 4 hours so we can safely assume its B

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