Answer:
Friction and Automobile Tires. ... On dry surfaces you might get as high as 0.9 as a coefficient of friction, but driving them on wet roads would be dangerous since the wet road coefficient might be as low as 0.1
Explanation:
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Answer:
C₃H₈(g) + 6 H₂O(g) ⇒ + 10 H₂(g) + 3 CO₂(g)
Explanation:
Propane can be turned into hydrogen by the two-step reforming process.
In the first step, propane and water react to form carbon monoxide and hydrogen. The balanced chemical equation is:
C₃H₈(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g)
In the second step, carbon monoxide and water react to form hydrogen and carbon dioxide. The balanced chemical equation is:
CO(g) + H₂O(g) ⇒ H₂(g) + CO₂(g)
In order to get the net chemical equation for the overall process, we have to multiply the second step by 3 and add it to the first step. Then, we cancel what is repeated.
C₃H₈(g) + 3 H₂O(g) + 3 CO(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g) + 3 H₂(g) + 3 CO₂(g)
C₃H₈(g) + 6 H₂O(g) ⇒ + 10 H₂(g) + 3 CO₂(g)
It speeds up the dissolving of the sugar. Agitation
Answer:
2H₂O₂ → 2H₂O + O₂
24.7 L are the liters of formed oxygen.
Explanation:
We state the reaction:
2H₂O₂ → 2H₂O + O₂
2 moles of peroxide decompose to 2 moles of water and 1 mol of oxygen gas.
We convert the mass to moles: 75 g . 1 mol / 34 g = 2.20 moles
As ratio is 2:1, per 2.20 moles of peroxide I would produce the half of moles, of O₂ → 2.20 /2 = 1.10 moles
We convert the moles to mass → 1.10 mol . 32 g / 1 mol = 35.3 g
Let's use oxygen's density to find out the volume
δ O₂ = 1.429 g/L (mass/volume)
35.3 g . 1L / 1.429g = 24.7 L
