The Temperature of the earth gets______ as you get closer to the _______ and ________ as you move towards the____

mina [271]

Answer: Chemistry is the study of change. Various reasons why to study Chemistry is to appreciate the fundamentals of the world such as the composition of all living thing. We are made up of matter. The interaction of sub atomic particles in an atom to form a single being. Also to understand how certain chemicals are beneficial and harmful in our lives just by reading product labels.

Explanation:

3 0

3 years ago

For the reaction shown, identify the element oxidized, the element reduced, the oxidizing agent, and the reducing agent. KNO3 →

Vinvika [58]

Answer : The oxidizing element is N and reducing element is O.

$KNO_{3}$ is act as an oxidizing agent as well as reducing agent.

Explanation :

An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.

Reducing agent is the agent which has ability to reduce other or lower in oxidation number.

The given reaction is :

$KNO_{3} \rightarrow KNO_{2} +O_{2}$

$KNO_{3}$ act as an oxidizing agent.

The oxidation number of N in $KNO_{3}$ is calculated as:

(+1)+(x)+3(-2) = 0

x = +5

And the oxidation number of N in $KNO_{2}$ is calculated as:

(+1)+(x)+2(-2) = 0

x = +3

From the oxidation number method, we conclude that the oxidation number reduced this means $KNO_{3}$ itself get reduced to $KNO_{2}$ and it can act as an oxidizing agent.

$KNO_{3}$ act as a reducing agent.

$KNO_{3} \rightarrow KNO_{2} +O_{2}$

The oxidation number of O in $KNO_{3}$ is calculated as:

(+1)+(+5)+3(x) = 0

x = -2

The oxidation number of O in $O_{2}$ is Zero (o).

Now, we conclude that the oxidation number increases this means $KNO_{3}$ itself get oxidized to $O_{2}$ and it can act as reducing agent.

4 0

3 years ago

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? Answer the question below. Type your response in the space provided. What volume of a 2.5 M stock solution of acetic acid (HC2

Novay_Z [31]

Data:
$M_{concentrated} = 2.5\:mol$
$V_{concentrated} = ?$
$M_{dilute} = 0.50\:mol$
$V_{dilute} = 100\:mL\to0.100\:L$

Formula: Dilution Calculations

 $M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}$

Solving:


$M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}$
$2.5 * V_{concentrated} = 0.50 * 0.100$
$2.5V_{concentrated} = 0.05$
$V_{concentrated} = \frac{0.05}{2.5}$
$\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark$

3 0

3 years ago

What is the equilibrium constant of pure water at 25°C?

ANEK [815]

The equilibrium reaction, causes the water dissociation constant, Kw, is 1.01 × 10-14 at 25 °C. That is because every H+ (H3O+) ion these forms accompanied by the formation of an OH- ion, are the concentrations of these ions and in pure water the same thing can be calculated from Kw.

HOPED THIS HELP OUT ;)

6 0

3 years ago

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Identify the ion ratios needed to form neutral compounds from the ions below. The metal ion (cation) is listed first, and the no

Natasha2012 [34]

To figure out the ratios of these compounds, it is important to remember that the charge of these compounds must be neutral.

So in order to make them neutral, you must have specific ratios:

$Na^{+}: Br^{-} =1:1$ ; This is true because they both have a charge of magnitude of 1.

$Al^{3+}: Cl^{-}=1:3$ ; We need 3 chlorine atoms because we need to balance out the charge from the 3+ charge of aluminum - therefore since chlorine has a 1- charge, we need 3 atoms.

$Mg^{2+}: O^{2-}=1:1$ ; The charges of the magnesium (2+) are balanced with the oxygen charge (2-).

$Al^{3+}: O^{2-}=2:3$ ; This is correct because if charges are like this, you must find the least common factor in order to know the ratio. The LCF is 6, therefore, for the atom with a 3+ charge, you need 2 of them, and for the atom with a 2- charge, you need 3 of them. This keeps the charge neutral.

7 0

3 years ago

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The Temperature of the earth gets______ as you get closer to the _______ and ________ as you move towards the_____

The Temperature of the earth gets__ as you get closer to the _ and __ as you move towards the_